Compute percent uncertainty of Resistor

[g.sharm89]

Homework Statement

The relationship between resistance with temperature is expressed by the equation of R= R0[1+ α(T-T0)], where Ro is the resistance at the reference temp. T0 and α for the resistor material has been determined to be 0.0048 ± 0.1% oC. In the range 0 to 100* C, in which we are calibrating this resistor, temperature measurements have shown a standard deviation of 0.1* C. The systematic uncertainty of the temperature- measurement device is known to be 0.1* C.
At 0* C, the resistance is 100.00 Ω. compute the percent uncertainty of R, at a temperature of 25* C with a 95% confidence level.

Homework Equations

R= R0[1+ α(T-T0)]

The Attempt at a Solution

α = .05
R= (100ohm) [1+ .05 (25-0)] = 225 ohm

 

[Stephen Tashi]

α = .05
R= (100ohm) [1+ .05 (25-0)] = 225 ohm

Well, you have a sense of humor!

Are there other problems like this in your course materials? I'm curious how they interpret statements such as:

The systematic uncertainty of the temperature- measurement device is known to be 0.1* C.

Do they assume there is a 1.0 probability that mean measurement will be within plus or minus 0.1 C of the correct value?