Temperature dependence of Resistance

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Homework Help Overview

The discussion revolves around the temperature dependence of resistance in a wire, specifically focusing on calculating the temperature coefficient of resistance using given resistance values at different temperatures.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore two methods for calculating the temperature coefficient of resistance, questioning the validity of using different reference temperatures. There is a discussion on the implications of using resistance at 0°C versus resistance at another temperature.

Discussion Status

Participants are actively engaging with the problem, raising questions about the assumptions made regarding the resistance at 0°C and discussing the differences between mean and actual temperature coefficients of resistance. Some guidance has been offered regarding the equations used, but no consensus has been reached on the preferred method.

Contextual Notes

There is uncertainty regarding the resistance at 0°C, which is not provided in the problem statement. This missing information influences the approaches taken by participants in their calculations.

zorro
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Homework Statement


A wire has a resistance of 2 ohm at 25 C and 2.5 ohm at 100 C . Find the temperature coefficient of resistance of the wire.

The Attempt at a Solution



This question is a very easy one, but I had a doubt -
R=Ro(1 + αθ)
Here θ is the change in temperature.

I proceed in 2 ways:
1) We can take Ro = 2 ohm at 25 C so that the equation becomes
2.5 = 2 [1 + α(100-25)]
On solving, α=3.33 x 10-3

2) Take Ro as the resistance at 0 C

2 = Ro(1 + 25α)
2.5 = Ro(1 + 100α)

On solving, α = 3.64 x 10-3

Which one is correct and why?
 
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How do you know the resistance at 0C?
 
R1 = Ro( 1 + αθ1)

R2 = Ro(1 + αθ2)

When you solve for α, you will get

α = (R2 - R1)/(R1θ2 - R2θ1)

Now find α.
 
rock.freak667 said:
How do you know the resistance at 0C?

I don't know the resistance. On dividing the two equations, Ro gets cancelled.
 
rl.bhat said:
R1 = Ro( 1 + αθ1)

R2 = Ro(1 + αθ2)

When you solve for α, you will get

α = (R2 - R1)/(R1θ2 - R2θ1)

Now find α.

Why can't we use just one equation as I showed?...thats my doubt.
 
In the first case, we get mean temperature coefficient of resistance for a selected pair of temperatures.

In the second case, it is the actual α for particular temperature.
 
rl.bhat said:
In the first case, we get mean temperature coefficient of resistance for a selected pair of temperatures.

In the second case, it is the actual α for particular temperature.

Is it that the actual temperature coefficient of resistance is measured w.r.t. the resistance at 0 C?
 
Abdul Quadeer said:
Is it that the actual temperature coefficient of resistance is measured w.r.t. the resistance at 0 C?

Yes. In the table of constants, α for different materials is given for 20oC.
 

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