Compute the integral of the Gaussian

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    Gaussian Integral
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Homework Help Overview

The discussion revolves around computing the integral of the Gaussian function, particularly in the context of Fourier transforms. Participants express uncertainty regarding the use of the error function and the implications of multiple Fourier transforms.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster questions the terminology of "transforms" and expresses confusion about the relationship between the Fourier transform and its inverse. They also mention a specific integral involving the error function and seek alternative methods for integration.
  • Some participants suggest using a "complete-the-square" substitution to simplify the integral, while also noting the need to justify the limits of integration when dealing with complex variables.
  • Further attempts to manipulate the integral are shared, including substitutions and transformations that lead to expressions involving the exponential function and the error function.

Discussion Status

The discussion is ongoing, with participants exploring various mathematical manipulations and substitutions. There is no explicit consensus, but several lines of reasoning and approaches are being examined, indicating a productive exploration of the problem.

Contextual Notes

Participants are navigating the complexities of integrating a Gaussian function within the framework of Fourier transforms, with some expressing uncertainty about the definitions and assumptions related to the error function and complex variables.

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why does it say transforms? is there more than one Fourier transform?? we learned in class that the inverse Fourier transform of the Fourier transform of ##f## is ##f##, so there should be just one right? I'm uncertain of how to calulate this integral though.. Mr Wolfram showed me an indefinite integral involving an error function, but there has to be a different way to integrate it because we didn't learn about the error function. Mr Wolfram says

$$\int_{-\infty}^\infty fe^{-ikx}dx=\sqrt{\pi}\sigma e^{(\frac{\sigma k}{2})^2}e^{-ikx_0}$$

how does one go from the beginning to the finish?
 
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Write\begin{align*}
\tilde{f}(k) &= \int_{-\infty}^{\infty} \mathrm{exp}\left( -ikx - \frac{(x-x_0)^2}{\sigma^2} \right) dx \\
&= e^{-ikx_0} \int_{-\infty}^{\infty} \mathrm{exp}\left( -ik(x-x_0) - \frac{(x-x_0)^2}{\sigma^2} \right) dx\end{align*}from here a 'complete-the-square' substitution like ##u = \dfrac{x-x_0}{\sigma} + \dfrac{i\sigma k}{2}## looks helpful, but take some care to justify the limits of the integral over ##u## given that ##u## is complex.
 
Last edited:
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ergospherical said:
Write\begin{align*}
\tilde{f}(k) &= \int_{-\infty}^{\infty} \mathrm{exp}\left( -ikx - \frac{(x-x_0)^2}{\sigma^2} \right) dx \\
&= e^{-ikx_0} \int_{-\infty}^{\infty} \mathrm{exp}\left( -ik(x-x_0) - \frac{(x-x_0)^2}{\sigma^2} \right) dx\end{align*}from here a 'complete-the-square' substitution like ##u = \dfrac{x-x_0}{\sigma} + \dfrac{i\sigma k}{2}## looks helpful, but take some care to justify the limits of the integral over ##u## given that ##u## is complex.
\begin{align} \tilde{f}(k) =& \int_{-\infty}^{\infty} \mathrm{exp}\left( -ikx - \frac{(x-x_0)^2}{\sigma^2} \right) dx \\
=e^{-ikx_0} &\int_{-\infty}^{\infty} \mathrm{exp}\left( -ik(x-x_0) - \frac{(x-x_0)^2}{\sigma^2} \right)dx\\
=e^{-ikx_0} &\int_{-\infty}^{\infty} \mathrm{exp}\left( -\frac{\sigma^2i^2k^2}{4}+\frac{\sigma^2i^2k^2}{4}-ik(x-x_0) - \frac{(x-x_0)^2}{\sigma^2} \right)dx\\
=e^{-ikx_0-\frac{\sigma^2i^2k^2}{4}} &\int_{-\infty}^{\infty} \mathrm{exp}\left( -(\frac{\sigma i k}{2}+\frac{x-x_0}{\sigma})^2 \right)dx\end{align}
let ##u = \dfrac{x-x_0}{\sigma} + \dfrac{i\sigma k}{2}##. since ##u## is complex, it leads to integrating for ##u\in\{(-\infty,\infty)\times \{0\}\}##.
\begin{align}&\sigma e^{-ikx_0-\frac{\sigma^2i^2k^2}{4}}\int_ u e^{-u^2}du\\
=&\sigma e^{-ikx_0-\frac{\sigma^2i^2k^2}{4}} \Big[\frac{\sqrt{\pi}}{2}\text{erf}(u)\Big]_u\\
=&\sigma \sqrt{\pi} e^{-ikx_0+\frac{\sigma^2k^2}{4}}\end{align}
 
Last edited:
is it ok?
:)
 

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