- #1
WMDhamnekar
MHB
- 376
- 28
- Homework Statement
- ##f(x,y) =xy^2i + xy^3 j ; ## C: the ploygonal path from (0,0) to (1,0) to (0,1) to (0,0)
- Relevant Equations
- None
This is not correct. Signs matter. OP should be able to deduce the correct path.Delta2 said:I think the correct one is x=t,y=1−t.
Sorry I don't see a sign error, its the straight line path from (1,0) to (0,1) (t has to vary from 1 to 0 though not from 0 to 1).Orodruin said:This is not correct. Signs matter. OP should be able to deduce the correct path.
OP has all integrals from 0 to 1. Unless explicitly stated that would be the typical assumption.Delta2 said:Sorry I don't see a sign error, its the straight line path from (1,0) to (0,1) (t has to vary from 1 to 0 though not from 0 to 1).
Yes.WMDhamnekar said:Is this answer correct?
That you went backwards, in a sense.WMDhamnekar said:If correct, why is the answer negative? What does this negative answer indicate?
In general, it won't be easy to see whether the answer is positive or negative. But, if you have a positive integrand in the first quadrant, then left to right and upwards is positive; right to left and upwards is negative (what we have here); left to right and downwards is negative; and, right to left and downwards is positive.Delta2 said:@PeroK your interpretation though correct is a bit shallow , there is something a bit more deep relating on how the vector field's direction relates to the direction we transverse the path.
I admit you confused me a bit here, but you seem to be thinking in terms of the integral we get after we do the parameterization.PeroK said:In general, it won't be easy to see whether the answer is positive or negative. But, if you have a positive integrand in the first quadrant, then left to right and upwards is positive; right to left and upwards is negative (what we have here); left to right and downwards is negative; and, right to left and downwards is positive.
The notation ##\displaystyle\int_C f\cdot dr## represents the line integral of a vector field, where f is the vector field and C is the curve over which the integral is being calculated. This integral measures the total effect of the vector field along the curve C.
To calculate ##\displaystyle\int_C f\cdot dr##, you first need to parameterize the curve C with a function r(t). Then, substitute this function into the integral and evaluate it using the appropriate integration techniques.
The line integral of a vector field measures the work done by the vector field along the curve C. It can also be used to calculate other physical quantities, such as flux and circulation.
Yes, the line integral of a vector field can be negative. This indicates that the vector field is doing work in the opposite direction of the curve C.
Line integrals of vector fields have various applications in physics, engineering, and economics. They can be used to calculate the work done by a force field, the flow of a fluid, or the circulation of a current. They are also used in optimization problems and in calculating the total cost of a project.