Concave Mirror Homework - Find Object Dist.

  • Thread starter Thread starter Boxter
  • Start date Start date
  • Tags Tags
    Concave Mirrors
Click For Summary

Homework Help Overview

The problem involves a concave mirror with a focal length of 20 cm, where the image formed is three times the height of the object. The original poster seeks to determine the object distance from the mirror for both real and virtual images.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between object distance, image distance, and magnification, referencing the equations related to mirrors. There are attempts to clarify the magnification value and its implications for the problem.

Discussion Status

The discussion is ongoing, with participants providing hints and exploring the implications of the magnification value. Some participants express confusion about how to apply the equations to find the object distance, while others suggest focusing on the magnification ratio.

Contextual Notes

Participants are working under the constraints of a homework assignment, and there is mention of answers being available in a textbook, which adds to the challenge of deriving the solution independently.

Boxter
Messages
8
Reaction score
0

Homework Statement


A concave mirror of focal length 20cm forms an image which is three times the height of the object. Find the distance of the object from the mirror if: 1: The image is real
2: The image is virtual

Homework Equations


1/u + 1/v = 1/f
m = v/u

The Attempt at a Solution


f = 20cm
u = ?
v = ?
 
Physics news on Phys.org
Welcome to Physics Forums.

The magnification tells you the ratio v/u, though it could be either positive or negative.
 
Redbelly98 said:
Welcome to Physics Forums.

The magnification tells you the ratio v/u, though it could be either positive or negative.

Sorry, but I still don't understand :confused:
 
Okay, think about it this way: based on the given information, we can say that
v = ____ × u
where you must fill in the blank with a number.
 
Is the object <answer deleted by moderator> away?
 
Last edited by a moderator:
I have the answers on the back of the book but can't figure out how to get it
 
And I will try one more hint. You wrote this equation earlier:
Boxter said:
m = v/u
What is the value of the magnification m, based on the information given in the problem statement?
 
Redbelly98 said:
And I will try one more hint. You wrote this equation earlier:

What is the value of the magnification m, based on the information given in the problem statement?

Magnification is 3 ??
 
If I divide 3 into 20 I get 6.666667. If I add 6.6667 to 20, is that how I get the real height, then take 6.66667 from 20 to get virtual height?
 
  • #10
Boxter said:
If I divide 3 into 20 I get 6.666667. If I add 6.6667 to 20, is that how I get the real height, then take 6.66667 from 20 to get virtual height?
Uh, I don't think so. You get the answer by working with the two equations you wrote earlier.
Boxter said:
Magnification is 3 ??
Yes, good. So your two equations your wrote in Post #1 become:

1/u + 1/v = 1/f
___ = v/u​

(Fill in the blank to get the complete equation.)
 

Similar threads

Replies
7
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
22
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
9
Views
8K
  • · Replies 1 ·
Replies
1
Views
2K