Concept Questions regarding Work

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SUMMARY

The statement that the lighter mass will travel further along the rough region before stopping is False. Both objects, regardless of mass, experience the same coefficient of kinetic friction, which means they will decelerate at the same rate once they reach the rough horizontal region. The equations governing this scenario include Work = Force•displacement•cosθ, Kinetic Energy = 0.5•m•v², and Potential Gravitational Energy = m•g•h. The key insight is that mass cancels out when analyzing the motion after the slope.

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Homework Statement



Two objects with unequal mass are released from rest from the same height. They slide without friction down a slope and then encounter a rough horizontal region. The coefficient of kinetic friction in the rough region is the same for both masses. The lighter mass will travel further along the rough region before stopping.
True or False?

Homework Equations



Work = Force•displacement•cosθ (angle between force and displacement)
Kinetic Energy = .5•m•v^2
Potential Gravitational Energy: m•g•h

The Attempt at a Solution



The answer is False; but I can't grasp the concept.
 
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TJDF said:

Homework Statement



Two objects with unequal mass are released from rest from the same height. They slide without friction down a slope and then encounter a rough horizontal region. The coefficient of kinetic friction in the rough region is the same for both masses. The lighter mass will travel further along the rough region before stopping.
True or False?

Homework Equations



Work = Force•displacement•cosθ (angle between force and displacement)
Kinetic Energy = .5•m•v^2
Potential Gravitational Energy: m•g•h

The Attempt at a Solution



The answer is False; but I can't grasp the concept.

Why not?

Write out the equation for what happens.

m*g*h = 1/2*m*v2 - u*m*g*d

What happens if you divide the equation by m?
 

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