- #1
sj005
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I think I know the answers to the question I am going to ask but I am just going to make sure. This is going to be quite simple for most of the experts here so here goes:
If we have a parallel plate capacitor and we double the distance between the plates while keeping the charge Q on the plates fixed. What will happen to:
a)The Capacitance
b)The Potential Difference
c)The Electric Field between the Plates
d)The Stored Energy
I studied the formulas/concepts and the answers I predicted were
a) The capacitance will be halved
b) The potential difference will double
c) The electric field will double
d) The energy stored will be twice as much
Are my answers correct or are they completely off?
Thanks in advance :)
If we have a parallel plate capacitor and we double the distance between the plates while keeping the charge Q on the plates fixed. What will happen to:
a)The Capacitance
b)The Potential Difference
c)The Electric Field between the Plates
d)The Stored Energy
I studied the formulas/concepts and the answers I predicted were
a) The capacitance will be halved
b) The potential difference will double
c) The electric field will double
d) The energy stored will be twice as much
Are my answers correct or are they completely off?
Thanks in advance :)