Conceptual RC Circuit questions

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SUMMARY

The discussion focuses on analyzing the behavior of an RC circuit after the switch is closed for an extended period. It concludes that the current through the capacitor (C) is zero at steady state, as it becomes fully charged, resulting in no current flowing through components A and the battery. The voltage across components A and the battery is 0V, while components B and C share the total voltage dictated by the battery, Vbat. The participants emphasize the importance of recognizing the capacitor's role in blocking current flow and the implications of voltage division in the circuit.

PREREQUISITES
  • Understanding of RC circuit behavior and steady-state conditions
  • Knowledge of voltage division principles in electrical circuits
  • Familiarity with capacitor charging and discharging processes
  • Basic concepts of current flow in parallel circuits
NEXT STEPS
  • Study the behavior of capacitors in series and parallel configurations
  • Learn about voltage dividers and their applications in circuit design
  • Explore the concept of time constants in RC circuits
  • Investigate the effects of different load resistances on capacitor discharge rates
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Electrical engineering students, hobbyists working with RC circuits, and anyone seeking to deepen their understanding of capacitor behavior in steady-state conditions.

DrummingAtom
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Homework Statement



After a long time after the switch is closed.

1) Rank the current of each component.
2) What is the voltage across each component?

Homework Equations





The Attempt at a Solution



1) The current across B is the same as the capacitor C because the capacitor is fully charged. There is no current across Vbattery and A because the capacitor now has positive charges on the top and negative charges on the bottom so there is no potential outside the parallel part (B and C).

2) 0 V for A and Vbattery. But B and C have the total voltage across each.

Is this right?

I'm thinking that the parallel part creates it's own self powered loop and blocks out the rest, the battery and A.

Thanks for any help.
 

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Current flows THROUGH. Voltage appears ACROSS.

After a long time the capacitor voltage settles to whatever the circuit around it dictates. In this case it won't be equal to the battery voltage because the lamps are creating a voltage divider. To see this, use the rule of thumb that says that at steady state the capacitor current will be zero and its voltage fixed, so for all intents and purposes you can simply ignore it (remove it from the circuit entirely). What does the remaining circuit look like?
 
DrummingAtom said:

Homework Statement



After a long time after the switch is closed.

1) Rank the current of each component.
2) What is the voltage across each component?

Homework Equations


The Attempt at a Solution



1) The current across B is the same as the capacitor C because the capacitor is fully charged. There is no current across Vbattery and A because the capacitor now has positive charges on the top and negative charges on the bottom so there is no potential outside the parallel part (B and C).
Sorry, this is totally wrong.
The capacitor is parallel connected to B. Why should the same current flow through both? What is the same across them?
The voltage of the battery is given, Vbat. Is there a closed path between the terminals through A and B? Can current flow from the positive pole of the battery to the negative one?

DrummingAtom said:
2) 0 V for A and Vbattery. But B and C have the total voltage across each.

Is this right?

No. The voltage of the battery is constant, Vbat. ehild
 

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