Condition for equality between subspaces.

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Homework Help Overview

The discussion revolves around the conditions under which a vector space V, spanned by the set K={v1,v2,v3,v4}, is equal to a subspace W defined by specific linear combinations of the vectors in K. Participants are exploring the implications of linear independence and the relationships between the vectors in K and the vectors that define W.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the condition for equality between the vector space V and the subspace W, particularly focusing on the linear independence of the vectors that define W. There are attempts to express conditions mathematically, but the focus remains on understanding the implications for the vectors in K.

Discussion Status

The discussion is active, with participants questioning the definitions and relationships between linear independence and the conditions for V to equal W. Some guidance has been offered regarding the need for linear independence, but there is no explicit consensus on the conditions for the vectors in K themselves.

Contextual Notes

Participants note that the exploration is constrained by the requirement to find conditions on the vectors in K rather than on scalars, leading to a deeper inquiry into the nature of linear combinations and dependencies among the vectors.

peripatein
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Hi,

Homework Statement



What would be the/a condition on vectors in K so that V=W, where V is a vector space which K={v1,v2,v3,v4} spans, and W is a subspace of V defined thus:
W=Sp{v1+v2,v2+v3,v3+v4,v4+v1}

Homework Equations





The Attempt at a Solution



I believe V would be equal to W if W were linearly independent, but by writing that mathematically I get a condition for the scalars, not the vectors in K themselves.

I hope one of you could assist. Thanks in advance!
 
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peripatein said:
Hi,

Homework Statement



What would be the/a condition on vectors in K so that V=W, where V is a vector space which K={v1,v2,v3,v4} spans, and W is a subspace of V defined thus:
W=Sp{v1+v2,v2+v3,v3+v4,v4+v1}

Homework Equations





The Attempt at a Solution



I believe V would be equal to W if W were linearly independent,

I know what you mean, but your terminology is wrong. You can't say that W is linearly independent because it is not true. What you mean is that the four vectors

\{v_1+v_2,v_2+v_3,v_3+v_4,v_4+v_1\}

are linearly independent. That would indeed be the correct condition.

but by writing that mathematically I get a condition for the scalars, not the vectors in K themselves.

I hope one of you could assist. Thanks in advance!

What did you get when you wrote that mathematically??
 
I have tried to find conditions so that:
a1v1 + a2v2 + a3v3 + a4v4 = v1(b1+b4) +
v2(b2+b1) + v3(b3+b2) + v4(b4+b3).
But that yielded conditions on the scalars, not the vectors. Can conditions on the vectors themselves be found?
 
peripatein said:
I have tried to find conditions so that:
a1v1 + a2v2 + a3v3 + a4v4 = v1(b1+b4) +
v2(b2+b1) + v3(b3+b2) + v4(b4+b3).
But that yielded conditions on the scalars, not the vectors. Can conditions on the vectors themselves be found?

How did you get that? In order for \{v_1+v_2,v_2+v_3,v_3+v_4,v_4+v_1\} to be a basis, you must prove that any linear combination of the form

\alpha(v_1+v_2)+\beta(v_2+v_3)+\gamma (v_3+v_4)+\delta(v_4+v_1)=0

only if \alpha=\beta=\gamma=\delta=0.

Now, try to use that \{v_1,v_2,v_3,v_4\} is a basis.
 
These yielded alpha=-delta=-beta=gamma.
But how does this affect the vectors in K themselves? I mean, what is then the condition on v1,v2,v3,v4?
 
peripatein said:
These yielded alpha=-delta=-beta=gamma.
But how does this affect the vectors in K themselves? I mean, what is then the condition on v1,v2,v3,v4?

OK, so what if you take the equation

\alpha(v_1+v_2)+\beta(v_2+v_3)+\gamma(v_3+v_4)+ \delta(v_4+v_1)=0

and if you substitute \alpha for \gamma and -\alpha for \delta and \beta?
 
You get alpha*0=0. How does that help?
 
peripatein said:
You get alpha*0=0. How does that help?

It shows that there is always a nontrivial linear combination that ends up in zero. Doesn't that show that your set \{v_1+v_2,v_2+v_3,v_3+v_4,v_4+v_1\} is never linearly independent?
 
Let us go back a bit, momentarily.
I am slightly confused. Why is it that for V to be equal to W, the elements in W must be linearly independent? Is it because dimV is equal to or less than the number of elements in K, i.e. 4?
Furthermore, I know that if the elements in K are linearly independent, then V is not equal to W. Does that mean that for any K whose elements are linearly dependent, V would be equal to W?
 

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