Conditional Epectation of Multinomial

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To calculate E(X1, X2 | Xn) in a multinomial distribution, it's essential to recognize that the variables are not independent. The expectation E(Xi) equals nPi, where Pi represents the probability of each category. The distribution of (X1, X2 | Xn = 6) is expected to follow a multinomial distribution with the total reduced by 6, adjusting the probabilities for X1 and X2 accordingly. Clarification on notation indicates that E(X1, X2) refers to the joint expectation of X1 and X2. Understanding these relationships is crucial for accurate calculations in multinomial contexts.
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So I'm trying to find E(X1,X2|Xn) where X1,X2,...Xn are the numbers of cell observations in a multinomial distribution. How do I even calculate this? I know it is not independent so I cannot split it.

Does it have something to do with the fact that E(Xi)=nPi ?
 
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Intuitively, we would expect the distribution of (X1, X2| Xn = 6) to be a multinomial distribution for 6 less objects with the cell probabilities for X1, X2,..X[n-1] scaled by a factor so they sum to 1. I don't know what your notation E(X1,X2... means. Are you asking about a vector of expectations?
 
Stephen Tashi said:
Intuitively, we would expect the distribution of (X1, X2| Xn = 6) to be a multinomial distribution for 6 less objects with the cell probabilities for X1, X2,..X[n-1] scaled by a factor so they sum to 1. I don't know what your notation E(X1,X2... means. Are you asking about a vector of expectations?

Interesting. Makes sense.

Well, E(X1,X2) is just expectation of x1 and x2
 
I was reading a Bachelor thesis on Peano Arithmetic (PA). PA has the following axioms (not including the induction schema): $$\begin{align} & (A1) ~~~~ \forall x \neg (x + 1 = 0) \nonumber \\ & (A2) ~~~~ \forall xy (x + 1 =y + 1 \to x = y) \nonumber \\ & (A3) ~~~~ \forall x (x + 0 = x) \nonumber \\ & (A4) ~~~~ \forall xy (x + (y +1) = (x + y ) + 1) \nonumber \\ & (A5) ~~~~ \forall x (x \cdot 0 = 0) \nonumber \\ & (A6) ~~~~ \forall xy (x \cdot (y + 1) = (x \cdot y) + x) \nonumber...

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