Conducting shell conceptual question

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The discussion centers on the charge distribution in a thick-walled conducting spherical shell with a point charge at its center. The inner surface of the shell acquires a charge of +20 mC to balance the -20 mC point charge, resulting in zero charge within the conductor itself. The net charge on the shell is +10 mC, leading to a charge of -10 mC on the outer surface. Participants clarify that the "zero charge in the interior" refers to the metal of the shell, not the space inside. The final conclusion is that the outer surface must indeed carry a charge of -10 mC.
tsuyoihikari
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Homework Statement



A thick-walled, conducting spherical shell has charge q = +10 mC, inner radius R1 = 10cm, and outer radius R2 = 50 cm. A point charge Q = -20 mC is located at the center of the shell.

Describe the the charge distribution in the shell.


2. Given answer

+20 mC on the inner surface; zero charge in the interior of the sphere; -10 mC on the outer surface.

The Attempt at a Solution



I know that there can be no net charge with a gaussian surface drawn inside a conductor, so in order to balance out the point charge, there must be +20 mC of charge on the inner surface, and then there should be a net charge of +10 mC on the whole sphere, so there would be +10 mC on the outer surface. I don't understand why the charge in the interior is zero; shouldn't it be -20 mC because of the point charge?
 
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I think your argument is correct. The "zero charge in the interior of the sphere" likely means no charge in the metal of the shell, not in the empty space inside the shell.
 
But then what would the charge on the outer surface be? Would it be +10 mC or -10 mC?

With my logic, it should be +10 mC, but the answer gives -10 mC.
 
It will be -10 mC.

As the net charge on shell is +10 mC and charge on inside surface is +20mC
so let charge on outside surface is X

therefore, X + 20 = 10

so X = -10mC
 
oh okay, so charge on shell doesn't include charge in the very center at all.
Thank you very much Delphi51 and cupid.callin!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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