Conducting slidewire see system-Faraday's Law

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SUMMARY

The discussion focuses on a conducting slidewire system influenced by Faraday's Law, where a sliding wire with mass m and resistance R falls under gravity in a magnetic field B. The maximum velocity of the slidewire is derived using the equation ɛ = -B(dA/dt), leading to v = -ɛ/BL. The power dissipated at peak velocity is calculated using P = (I^2)R, resulting in P(dissipated) = (B^2L^2v^2)/R. The participants express uncertainty about the simplification of the problem and the inclusion of mass in the calculations.

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Homework Statement



A conducting slidewire system is set up as shown. The sliding wire has mass m and electrical resistance R and falls under gravity as shown. The fixed wire loop has zero resistance and lies perpendicular to a uniform magnetic field B shown pointing into the page.
i) Use Faraday's Law to determine the maximum velocity of the slidewire.
ii) How much power is dissipated at the peak velocity?

Homework Equations



ɛ=-dФ/dt
P=(I^2)R

The Attempt at a Solution


I defined the area vector as pointing in the same direction as the magnetic field, so
ɛ=-B(dA/dt)
In time dt the slidewire moves a distance vdt, giving ɛ=-BLv where L is the width of the slidewire.
I think I am simplifying the problem too much by simply rearranging for v in this equation and obtaining
v=-ɛ/BL -should I differentiate in order to maximise v? I feel I am missing something by not including the given mass m.

For the second part, overall current I=|ɛ|/R, so I=BLv/R
P=I^2R=(BLv/R)^2/R

P(dissipated)=(B^2L^2v^2)/R

Thanks in advance for any help, much appreciated.
 

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But with v=-ɛ/BL you haven't determined v yet, have you !?

Is there something that stops you from answering e.g. ## v = -{\tfrac 1 2} g t^2 ## ?

[edit]
Thanks in advance for any help, much appreciated
Not so certain my help has helped. Can you enlighten me ?
 
Last edited:

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