Conformal map to convert circle to a line

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SUMMARY

The discussion focuses on the use of the conformal mapping function z^2 + 1/z^2 to transform a circle into a line. This mapping effectively flattens a circle of radius 1, but requires modification to accommodate circles of different radii, specifically radius 'a'. Participants emphasize the importance of visualizing the mapping's effect on boundary surfaces, such as points on the real and imaginary axes, to understand the transformation better. The method of images is also mentioned as a potential approach for achieving the desired mapping.

PREREQUISITES
  • Understanding of complex analysis and conformal mappings
  • Familiarity with the concept of homographic projections
  • Knowledge of boundary surfaces in complex geometry
  • Ability to manipulate and visualize complex functions
NEXT STEPS
  • Research modifications to the mapping function z^2 + 1/z^2 for different circle radii
  • Explore the method of images in the context of conformal mapping
  • Learn about boundary behavior of complex functions
  • Experiment with complex number inputs to visualize mapping effects
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Mathematicians, physicists, and students of complex analysis who are interested in conformal mappings and their applications in geometry.

shehry1
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I need a conformal mapping that would map an ellipse or a circle to a line. I need this for the http://physics.indiana.edu/~berger/p506_fall2008/p506ps6.pdf" .

As far as I can understand, z^2 + 1/z^2 makes the geometry similar to that of a plane on the horizontal axis with a circle centered on the origin. I can use the method of images (I think) but I was thinking of another map that would flatten out the circle and keep that plane in its current form.

Not that it matters, I tried to tailor the homographic projection to my needs but couldn't get it to work.
 
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z^2 + 1/z^2 does flatten out the circle, if the circle has radius 1. You need to modify this map to flatten out a circle of radius a.

It is easiest to think about what the map does to each of the three boundary surfaces, independently; i.e., what happens to points on the real axis > a, on the imaginary axis > ia, and on the quarter-circle of radius a. If you can't visualize what happens, then try plugging in a complex number into the map to see where it goes (i.e., try x, iy, and ae^(it)).
 
Ben Niehoff said:
z^2 + 1/z^2 does flatten out the circle, if the circle has radius 1. You need to modify this map to flatten out a circle of radius a.

It is easiest to think about what the map does to each of the three boundary surfaces, independently; i.e., what happens to points on the real axis > a, on the imaginary axis > ia, and on the quarter-circle of radius a. If you can't visualize what happens, then try plugging in a complex number into the map to see where it goes (i.e., try x, iy, and ae^(it)).

Hmmm...seems very simple now that you have put it that way - guess that's the whole thing. Thanks a lot. Would try it as soon as I get the time
 
Also, keep in mind a line is just a circle passing throgh infinity. (In this geometry, I mean)
 

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