Confused about j hat in this magnetic field problem.

Click For Summary
SUMMARY

The discussion centers on calculating the force on a charged particle in a magnetic field using the formula F = q(v x B). The particle has a charge of -3.64 nC and a velocity of 2.75 x 10^3 m/s in the i direction, while the magnetic field is given as 0.75 T in the i direction and 0.75 T in the k direction. The confusion arises from the sign of the force, as the participant initially misinterprets the cross product and the effect of the negative charge. Ultimately, the participant realizes that the negative charge results in a force direction opposite to that of a positive charge.

PREREQUISITES
  • Understanding of vector cross products
  • Knowledge of magnetic fields and forces on charged particles
  • Familiarity with the right-hand rule for determining vector directions
  • Basic concepts of electric charge and its effects on motion
NEXT STEPS
  • Study vector cross products in detail, focusing on their geometric interpretation
  • Learn about the Lorentz force law and its applications in electromagnetism
  • Explore the right-hand rule and its use in determining force directions in magnetic fields
  • Review examples of charged particle motion in magnetic fields to solidify understanding
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone looking to deepen their understanding of forces on charged particles in magnetic fields.

charlies1902
Messages
162
Reaction score
0

Homework Statement


A point particle has a charge equal to –3.64 nC and a velocity equal to
2.75 10^3 m/s i. Find the force on the charge if the magnetic field is
(d) 0.75 Ti + .75Tk

The solution manual had a positive number. I thought it was a typo until I saw the next problem where they got the opposite sign of what I got again for j hat.
F=qv x B, how is it possible that they got a + #?
 
Physics news on Phys.org
I think that i x k = -j, just as you do. However, another negative sign enters into the equation by means of q, which is intrinsically negative here. Negative charges will move in the opposite direction of positive charges.
 
cepheid said:
I think that i x k = -j, just as you do. However, another negative sign enters into the equation by means of q, which is intrinsically negative here. Negative charges will move in the opposite direction of positive charges.
OMG I'm so stupid I completely forgot about that, been too long since I did cross products. thanks a lot
 

Similar threads

Replies
12
Views
2K
Replies
2
Views
1K
  • · Replies 25 ·
Replies
25
Views
2K
Replies
8
Views
2K
Replies
11
Views
4K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
1
Views
1K
Replies
1
Views
2K