Confused About Limit x->0- |x|: Seeking Explanation

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Homework Help Overview

The discussion revolves around the limit of the absolute value function as x approaches 0 from the left, specifically the expression limit x->0- |x|. Participants are exploring the interpretation of this limit and the responses provided by an instructor.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster expresses confusion regarding the instructor's answer of -1, believing the limit should be 0 as values approach from the left. Other participants question the instructor's response and suggest it may have been a typo. There is also a mention of a potential alternative interpretation involving the limit of |x|/x.

Discussion Status

The discussion is active, with participants sharing their thoughts and questioning the validity of the instructor's answer. Some guidance has been offered regarding the nature of absolute values and limits, but no consensus has been reached on the correct interpretation.

Contextual Notes

Participants are operating under the assumption that the limit should yield a value of 0, and there is a focus on clarifying the definitions and behaviors of the functions involved. The original poster's understanding of left-hand limits is also being examined.

khurram usman
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Homework Statement


the answer to this question [limit x->0- |x|] given to me by my instructor was -1. (by 0- i mean to say the left handed limit). i have been thinking for the last 15 minutes but could not understand it.

i think the answer should be 0 because as we get closer to zero from the left side the distance between 0 and our number gets smaller and smaller till finally it approaches 0 itself.

and as for the right hand limit of same question ( limit x->0+ |x|) i was given the answer 0 and that seems corret to me.
so anyone please explain this..
thanks
 
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khurram usman said:

Homework Statement


the answer to this question [limit x->0- |x|] given to me by my instructor was -1. (by 0- i mean to say the left handed limit). i have been thinking for the last 15 minutes but could not understand it.

i think the answer should be 0 because as we get closer to zero from the left side the distance between 0 and our number gets smaller and smaller till finally it approaches 0 itself.

and as for the right hand limit of same question ( limit x->0+ |x|) i was given the answer 0 and that seems corret to me.
so anyone please explain this..
thanks
You are correct, the limit of |x| as x \to 0 exists and is 0.

\lim_{x\to0^-} |x| = \lim_{x\to0^+} |x| = \lim_{x\to0} |x| = 0

Perhaps it was a typo in your instructor's answer.
 
Or perhaps the problem was intended to be
\lim_{x\to 0^-} \frac{|x|}{x}
 
khurram usman said:

Homework Statement


the answer to this question [limit x->0- |x|] given to me by my instructor was -1. (by 0- i mean to say the left handed limit). i have been thinking for the last 15 minutes but could not understand it.

i think the answer should be 0 because as we get closer to zero from the left side the distance between 0 and our number gets smaller and smaller till finally it approaches 0 itself.

and as for the right hand limit of same question ( limit x->0+ |x|) i was given the answer 0 and that seems corret to me.
so anyone please explain this..
thanks

Since you're approaching from the left what you're dealing with is a negative number and absolute value goes out as ( - x ) but x=0 so - x = - 0 = Zero
 

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