1. Sep 4, 2012 #1

   BWV

   

   I thought Lorentz Transformations left Δt²-Δx² invariant
   but, for example a frame moving at .5C for Δt =1 has Δx = .5 so
   Δt²-Δx² = .75
   
   If this is transformed by :
   
   
   
   
   
   to a rest frame
   Δt =0.65 has Δx = 0 and Δt²-Δx²≠ 0.75
   
   not sure where I have gone wrong here, any help would be appreciated

    

   BWV, Sep 4, 2012
2. 
   Phys.org - latest science and technology news stories on Phys.org

   • • Scarlet macaw DNA points to ancient breeding operation in Southwest
   • • Mathematicians solve age-old spaghetti mystery
   • • New technology can detect hundreds of proteins in a single sample
3. Sep 4, 2012 #2

   Samshorn

   

   You made a mistake with your arithmetic. If you plug your numbers into the Lorentz Transformation equation that you quoted, the result is Δt' = sqrt(0.75) and Δx' = 0, so the quantity Δt'²-Δx'² equals 0.75, just as before.

    

   Samshorn, Sep 4, 2012

• Log in with Facebook
• Log in with Twitter

Your name or email address:

Do you already have an account?

• No, create an account now.
• Yes, my password is:
• Forgot your password?

Stay logged in