1. Sep 4, 2012 #1

   BWV

   

   I thought Lorentz Transformations left Δt²-Δx² invariant
   but, for example a frame moving at .5C for Δt =1 has Δx = .5 so
   Δt²-Δx² = .75
   
   If this is transformed by :
   
   
   
   
   
   to a rest frame
   Δt =0.65 has Δx = 0 and Δt²-Δx²≠ 0.75
   
   not sure where I have gone wrong here, any help would be appreciated

    

   BWV, Sep 4, 2012
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3. Sep 4, 2012 #2

   Samshorn

   

   You made a mistake with your arithmetic. If you plug your numbers into the Lorentz Transformation equation that you quoted, the result is Δt' = sqrt(0.75) and Δx' = 0, so the quantity Δt'²-Δx'² equals 0.75, just as before.

    

   Samshorn, Sep 4, 2012

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