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Homework Help: COnfused: what is the derivative of ln(2x)?

  1. Oct 17, 2009 #1
    1. The problem statement, all variables and given/known data

    What is the derivative of ln(2x)?

    I was just thinking about this, and I got 2 answers. I am in Calc 2 right now.

    2. Relevant equations

    Derivative of ln(x) = 1/x

    3. The attempt at a solution

    Since d/dx lna = (1/a)*(derivative of a)

    Thus d/dx ln2x = (1/2x)*(2)


    I can also do this, I think: d/dx ln2x = 2d/dx lnx = 2*1/x = 2/x

    I am CONFUSED!! lol !:)

    Please tell me which is the correct method! :)

    Thanks! :)
  2. jcsd
  3. Oct 17, 2009 #2
    both the methods are incorrect
    d/dx(log 2x)=(1/2x)d/dx(2x)
  4. Oct 17, 2009 #3
    This is correct. Note that ln(ax) = ln(a) + ln(x). Since ln(a) is a constant, the derivative is always 1/x, irrespective of 'a'. In geometric terms, 'a' simply moves the graph of the logarithm up or down; it does not change the shape of the graph.

    This is wrong. The natural logarithm is not linear: you cannot pull the 2 out of the ln, irrespective of the derivative. ln(2x) is not 2ln(x) any more than cos(2x) = 2cos(x). It would be a good idea to review the definition and properties of logarithms.
  5. Oct 17, 2009 #4
    Thanks Slider and Monty!! :)
  6. Oct 18, 2009 #5
    (d(ln 2x)/ dx) / (d(2x)/ dx) = 2/2x/2 = 1/2x
  7. Oct 18, 2009 #6


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    Science Advisor

    100% wrong! Go back and read the previous responses to this question. The derivative is 1/x.
  8. Oct 18, 2009 #7
    ohh sorry I calculatd, derivative of ln2x wrt to 2x.
  9. Oct 19, 2009 #8
  10. Oct 19, 2009 #9


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    Homework Helper

    try reading the other posts... d(ln2x)/dx = 1/x
  11. Jan 18, 2010 #10
    anti derivative of 1/x or x^-1 = ln (x) natural log of x =ln x +c so the derivative of c + ln (2x)dx=1/2x +C'
  12. Jan 18, 2010 #11


    Staff: Mentor

    Wrong on two counts:
    1. d/dx(c) = 0 - not c'
    2. d/dx(ln(2x)) = 1/x - you are forgetting to use the chain rule.
  13. Jan 18, 2010 #12


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    Gold Member

    I didn't see it mentioned but observe also you can apply the properties of logarithms:

    [tex] d/dx \, \ln(2x) = d/dx\, [\ln(x) + \ln(2)] = 1/x + 0[/tex]
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