Confusing linear algebra problem

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SUMMARY

The discussion centers on a linear algebra problem involving two subspaces, U1 and U2, within a finite-dimensional vector space V. The user successfully proved that the intersection of W (span{v_1, v_2, ..., v_k}) and U2 is the zero vector, W ∩ U2 = {0}. They seek clarification on demonstrating that if U1 + U2 = V, then W ⊕ U2 = V, where W ⊕ U2 denotes the direct sum of W and U2. The dimension theorem is applied, confirming that the dimensions add up correctly under the given conditions.

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  • Familiarity with the dimension theorem in linear algebra
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Homework Statement



Let U1 and U2 be two subspaces of a finite dimensional vector space V , let {u_1,u_2...,u_m} be a basis of U1 /\U2(where /\ means intersection) and let {u_1,u_2...,u_m, v_1,v_2...,v_k} be an extension to a basis of U1 . Let W = span{v_1,v_2...,v_k}. I need to prove that that W /\U2 = {0}
and that, if U1 + U2 = V , then W # U2 = V,where W#U2 is the direct sum of W and U2.

Homework Equations



The Attempt at a Solution


I proved that W /\U2 = {0} with some help but I need help with the second part...but I'm more interested in an explanation as I find this problem...confusing
 
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By the dimension theorem dim(W # U2)=dim W+dim U2+ dim(W /\U2)...since W /\U2=0 dim(W /\U2)=0 and since W+U2=V =>dimW+dimU2=V=>W # U2 = V,is this correct?
 

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