Conic sections: Can focal points be outside the ellipse?

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SUMMARY

The focal points of an ellipse are always located inside the ellipse, as established by the equation of the ellipse given by x²/a² + y²/b² = 1, where b > a. The focal points are determined by the formula c² = a² - b², placing them on the y-axis for this configuration. As the eccentricity approaches zero, the ellipse becomes a circle, and as it approaches one, it becomes a parabola. Therefore, the assertion that focal points can be outside the ellipse is incorrect.

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  • Understanding of conic sections, specifically ellipses
  • Familiarity with the standard form of an ellipse equation
  • Knowledge of eccentricity in conic sections
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Bipolarity
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Can an ellipse's focal points be outside the ellipse? I have tried googling this, but without any good explanations or answers.

According to my calculations, the focal points of the ellipse defined by x^{2} + \frac{y^{2}}{4} = 1 are (-\sqrt{3},0) (\sqrt{3},0)).

I maybe wrong of course, but does this mean that the focal points of an ellipse can indeed be outside the ellipse?

BiP
 
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Bipolarity said:
Can an ellipse's focal points be outside the ellipse? I have tried googling this, but without any good explanations or answers.

According to my calculations, the focal points of the ellipse defined by x^{2} + \frac{y^{2}}{4} = 1 are (-\sqrt{3},0) (\sqrt{3},0)).

I maybe wrong of course, but does this mean that the focal points of an ellipse can indeed be outside the ellipse?

BiP

The focal points of an ellipse are always interior. In a plane, an ellipse is the set of points that are equidistant to two points.
 
Bipolarity said:
Can an ellipse's focal points be outside the ellipse? I have tried googling this, but without any good explanations or answers.

According to my calculations, the focal points of the ellipse defined by x^{2} + \frac{y^{2}}{4} = 1 are (-\sqrt{3},0) (\sqrt{3},0)).

I maybe wrong of course, but does this mean that the focal points of an ellipse can indeed be outside the ellipse?

BiP
Yes, that's wrong. If an ellipse is given by
\frac{x^2}{a^2}+ \frac{y^2}{b^2}= 1
with b> a, then the foci are at (0, c) and (0, -c) with c^2= a^2- b^2
so the foci of this ellipse are on the y-axis, not the x-axis.
 
In the limit as the eccentricity goes to zero, an ellipse becomes a circle; both focal points converge to the center. In the limit as the eccentricity goes to infinity, an ellipse becomes a line segment, where the focal points are at the endpoints. In between, the focal points are always inside the ellipse.
 
Ben Niehoff said:
In the limit as the eccentricity goes to zero, an ellipse becomes a circle; both focal points converge to the center. In the limit as the eccentricity goes to infinity, an ellipse becomes a line segment, where the focal points are at the endpoints. In between, the focal points are always inside the ellipse.
The eccentricity of an ellipse is always between 0 and 1 so it cannot "go to infinity". As the distance between foci goes to infinity, the eccentricity goes to 1.

Eccentricity 1 gives a parabola, eccentricity greater than 1 is a hyperbola.
 

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