- #1
Appleton
- 91
- 0
If a general conic is
[itex]
ax^2+2hxy+by^2+2gx+2fy+c=0
[/itex]
I am told that, if P(p, q) is a point on this conic, then the polar of P(p, q) to this conic is
[itex]
apx+h(py+qx)+bgy+g(p+x)+f(q+y)+c=0
[/itex]
How is this derived?
[itex]
ax^2+2hxy+by^2+2gx+2fy+c=0
[/itex]
I am told that, if P(p, q) is a point on this conic, then the polar of P(p, q) to this conic is
[itex]
apx+h(py+qx)+bgy+g(p+x)+f(q+y)+c=0
[/itex]
How is this derived?