Conical Pendulum: Solving the Height Issue

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Homework Help Overview

The discussion revolves around a conical pendulum problem, specifically addressing the relationship between the height of the pendulum bob and the length of the string. Participants are exploring the implications of given values and their feasibility in the context of the problem.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Some participants question the validity of the given values, suggesting they may not allow for a real solution. Others discuss the relationship between the periods of conical and planar pendulums, raising concerns about the implications of height exceeding string length.

Discussion Status

Participants are actively engaging with the problem, questioning assumptions and exploring the criteria for the conical pendulum's motion. There is a recognition of the need for further validation of the relationships discussed, particularly regarding the periods of different pendulum types.

Contextual Notes

There are indications that the problem may contain inconsistencies, particularly with the specified height and string length. The discussion includes references to specific criteria that must be met for the conical pendulum to function correctly.

Spencer25
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Homework Statement
A 3m long string is attached to a 5kg mass and rotates at 5 rpm. Calculate the height of the pendulum.
Relevant Equations
H=g/w2 (Height = gravity divided by angular velocity squared)
= 9.81/ .27415 = 35.78m
So in this instance height is longer than the 3m string which is impossible. Do we just say that when ever H>L, H=L?
 
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I suspect that the given values for this problem are incorrectly specified for a real solution to exist. Consider that at 5 rpm the bob would have a period per revolution of 12 seconds. The same setup but swinging like a normal (planar) pendulum would have a period of
$$2 \pi \sqrt{\frac{3 m}{g}} \approx 3.5 \text{ seconds}$$
Pretty sure the period of the conical pendulum should be less than or equal that of the planar version (haven't proved this yet, so it's just intuition at the moment).
 
I know the formula is correct as is the math...just must be missing some sort of rule?
 

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gneill said:
I suspect that the given values for this problem are incorrectly specified for a real solution to exist. Consider that at 5 rpm the bob would have a period per revolution of 12 seconds. The same setup but swinging like a normal (planar) pendulum would have a period of
$$2 \pi \sqrt{\frac{3 m}{g}} \approx 3.5 \text{ seconds}$$
Pretty sure the period of the conical pendulum should be less than or equal that of the planar version (haven't proved this yet, so it's just intuition at the moment).
Yes, the period of the conical pendulum is ##T=2\pi \sqrt{\frac{h}{g}}## where ##h## is the "height". Since ##h < L##, it is less than that of the planar pendulum unless, of course, the bob isn't moving.
 
Makes sense, thank you so much!
 
I find that the criteria is

$$L \omega^2 \ge g$$
else r becomes either zero or imaginary.
 
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gneill said:
I find that the criteria is

$$L \omega^2 \ge g$$
else r becomes either zero or imaginary.
Yes. Circular motion can be decomposed as a superposition of linear harmonic motions at right angles with a 90-degree phase shift. In the limit of small angles for the conical pendulum, the harmonic motions are just pendulum swings of small amplitude which we know have angular frequency ##\sqrt{g/L}##. You cannot make the conical pendulum have a smaller angular frequency than this.
 
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That is great...thanks again.
 
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