- #1
cmj1988
- 23
- 0
I 'cheated' and used GAP to compute these, but I want to make sure I am thinking through these properly. This isn't homework as much as given answers in an example and I'm not sure how they computed them.
S_12
(1,2)(3,4)(5,6)(7,8)(9,10)(11,12) - 10,395
This stems from
[tex]\binom{12}{2}\binom{10}{2}\binom{8}{2}\binom{6}{2}\binom{4}{2}
[/tex][tex]\frac{1}{6!}[/tex]
The 6! gets rid of redundant combinations. Is this right? I don't have a calculator handy so I'm not sure how to calculate that.
S_12
(1,2)(3,4)(5,6)(7,8)(9,10)(11,12) - 10,395
This stems from
[tex]\binom{12}{2}\binom{10}{2}\binom{8}{2}\binom{6}{2}\binom{4}{2}
[/tex][tex]\frac{1}{6!}[/tex]
The 6! gets rid of redundant combinations. Is this right? I don't have a calculator handy so I'm not sure how to calculate that.