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B Conservation of angular momentum

  1. Aug 12, 2016 #1
    Hello everyone!
    I have a problem , to which I do not understand the law of conservation of angular momentum... I searched this problem on the web and it is obvious that I am making the mistake.
    So we have a rod of length ##L## and mass ##m## that is lying on a horizontal frictionless table. We hit the rod at one end, perpendicular to the rod, with a ball of mass ##m## that is rolling on the table with initial speed ##v_0##. After they collide elastically , the rod begins rotational and translational motion with angular velocity ##\omega##(about its CM) and velocity ##v_1##(of the CM) , while the ball continues its translation with velocity ##v_2##, in the same direction as the initial velocity ##v_0##.
    Now , if we consider the moment of inertia of the rod about its center of mass to be ## I ## , I say that the conservation of angular momentum about the center of mass of the rod is:

    ## m \cdot v_0 \cdot \frac{L}{2} = m \cdot (v_2 - v_1) \cdot \frac{L}{2} + I \cdot \omega ##
    But the solution says:

    ## m \cdot v_0 \cdot \frac{L}{2} = m \cdot v_2 \cdot \frac{L}{2} + I \cdot \omega ##

    ##( I = m \cdot \frac {L^2}{12} )##

    why ?
    Isn't the conservation of angular momentum always relative to the center of mass of the rod?
     
    Last edited: Aug 12, 2016
  2. jcsd
  3. Aug 12, 2016 #2

    BvU

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    Hi,
    It's always. (period). And here you choose the center of mass for the calculation. ##v_1## can't appear in there. (but it does of course appear in the conservation of linear momentum)
     
  4. Aug 12, 2016 #3

    jbriggs444

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    Conservation of momentum applies when angular momentum is calculated about a fixed point which may or may not be the center of momentum of some particular object within your closed system and which may or may not be at the center of mass of the entire system. The key is that it is a fixed point. Anchoring it to an object which undergoes acceleration is a good way to have conservation of [angular] momentum not apply.

    In some treatments, the reference point is taken as the origin of a coordinate system in your chosen inertial frame. But one can use any point that is in uniform motion by simply translating to an [inertial] reference frame where that point is the origin.
     
    Last edited: Aug 15, 2016
  5. Aug 13, 2016 #4
    Before applying angular momentum conservation think about 2 things.
    First:
    point about which you are applying angular momentum conservation. Whether point is stationary or moving or accelerated.
    If accelerated you have to apply pseudo force to CENTER OF MASS OF THE SYSTEM ON WHICH YOU APPLY ANGULAR MOMENTUM CONSERVATION.
    Second: system on which you apply it. If there is net tourqe acting (including psuedo force torque) angular momentum conservation invalid.

    So here COM of rod is accelerated frame of reference, psuedo force has to be applied on system's COM i.e. on COM of rod plus bullet system. And definitely COM of rod does not match COM of system so you can't apply angular momentum conservation (psuedo force torque)
     
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