(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A skier starts from rest at the top of a hill. The skier coasts down the hill and up a second hill, as the drawing illustrates. The crest of the second hill is circular, with a radius of r = 47 m. Neglect friction and air resistance. What must be the height h of the first hill so that the skier just loses contact with the snow at the crest of the second hill?

http://img254.imageshack.us/img254/7408/0644bg0.gif [Broken]

2. Relevant equations

1/2mvf^{2}+mgHf=1/2mvo^{2}+mgho

3. The attempt at a solution

All the masses cancel out. I got the equation down to two unknowns, one is the initial height and the other is the final velocity. Now I'm stumped.

This is the furthest I've gotten: 1/2vf^{2}+g(47+h)=1/2vo^{2}+g(47-h)

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# Homework Help: Conservation of energy of a downhill skier

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