Conservation of Energy rollercoaster

AI Thread Summary
The discussion centers on calculating the total energy of a roller coaster at two points, A and B. At point A, the potential energy is calculated using the formula (mass)*(g)*(height), while at point B, the kinetic energy is calculated as 1/2(mass)(v)^2, resulting in 1600J. However, it is emphasized that the initial kinetic energy at point A must also be included in the total energy calculation, which should be 176 kJ when both potential and kinetic energies are considered. The principle of energy conservation indicates that the total energy remains constant as potential energy converts to kinetic energy when descending. Accurate calculations are crucial for understanding energy dynamics in roller coaster physics.
jhrnndz1
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I have a quetion that I worked out and would love to know if I worked it out alright. Here it goes...

A roller coaster of mass 80kg is moving with a speed of 20.0 m/s at position A with a height of 200m. There is no friction and g=10m/s^2.

So basically there's a diagram of a rollercoaster with different points and different heights.

What is the total energy of the rollercoaster at point A?

So, this is at the top of the rollercoaster, so I basically calculated the potential energy. (mass)*(g)*(height).

Next, what is the total energy of the roller coaster at point B, which has no height.

I calculated the kinetic energy 1/2(mass)(v)^2 and got 1600J

Did I do this correct?
 
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jhrnndz1 said:
I have a quetion that I worked out and would love to know if I worked it out alright. Here it goes...

A roller coaster of mass 80kg is moving with a speed of 20.0 m/s at position A with a height of 200m. There is no friction and g=10m/s^2.

So basically there's a diagram of a rollercoaster with different points and different heights.

What is the total energy of the rollercoaster at point A?

So, this is at the top of the rollercoaster, so I basically calculated the potential energy. (mass)*(g)*(height).

Next, what is the total energy of the roller coaster at point B, which has no height.

I calculated the kinetic energy 1/2(mass)(v)^2 and got 1600J

Did I do this correct?
Aren't you forgetting the initial kinetic energy? HINT: Is energy conserved?
 
Hello jhrnndz1,

you've missed that the roller coaster has kinetic energy at point A as well.

jhrnndz1 said:
A roller coaster of mass 80kg is moving with a speed of 20.0 m/s at position A with a height of 200m. There is no friction and g=10m/s^2.

Regards,

nazzard
 
jhrnndz1 said:
I have a quetion that I worked out and would love to know if I worked it out alright. Here it goes...

A roller coaster of mass 80kg is moving with a speed of 20.0 m/s at position A with a height of 200m. There is no friction and g=10m/s^2.

So basically there's a diagram of a rollercoaster with different points and different heights.

What is the total energy of the rollercoaster at point A?

So, this is at the top of the rollercoaster, so I basically calculated the potential energy. (mass)*(g)*(height).

Next, what is the total energy of the roller coaster at point B, which has no height.

I calculated the kinetic energy 1/2(mass)(v)^2 and got 1600J

Did I do this correct?

Energy conservation states that total potential + total kinetic = total energy, PE + KE = TE. For your question, TE at point A is 0.5(80)(20)^2 + 80(10)(200) = 176 KJ. At point B, when the roller coaster comes down, its TE is still the same as its PE is converted to KE, thus the roller coaster will have a greater KE, meaning more speed.
 
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