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yomii
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Homework Statement
if a basketball of mass=5kg is dropped from a height of 3 cm hits the ground and it compresses 0.015m then what is the spring constant
Conservation of Energy: Spring onstant
- Thread starter yomii
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SUMMARY
The discussion focuses on calculating the spring constant of a basketball dropped from a height of 3 cm, which compresses 0.015 m upon impact. Using the conservation of energy principle, the gravitational potential energy (Eg1) is equated to the elastic potential energy (Es2). The formula applied is mgh = (1/2)kx^2, where m is the mass (5 kg), g is the acceleration due to gravity (9.81 m/s²), h is the height (0.03 m), k is the spring constant, and x is the compression (0.015 m). This leads to the determination of the spring constant k.
PREREQUISITES- Understanding of gravitational potential energy
- Familiarity with elastic potential energy concepts
- Knowledge of the conservation of energy principle
- Basic algebra for solving equations
- Calculate the spring constant using the formula k = (2mgh) / x²
- Explore the relationship between mass, height, and energy in different contexts
- Investigate real-world applications of spring constants in engineering
- Learn about energy conservation in elastic collisions
Students studying physics, educators teaching mechanics, and anyone interested in understanding energy conservation principles in practical scenarios.