Conservation of Energy: Why are Normal Forces Zero?

AI Thread Summary
The work done by normal forces is zero because they act perpendicular to the displacement, resulting in an angle of 90 degrees, where the cosine equals zero. This relationship is defined by the equation for work, W = Fd cos(θ), which confirms that normal forces do not contribute to work. Additionally, the definition of work involves the dot product of force and displacement, which also results in zero when the forces are perpendicular. There is a clarification regarding the direction of normal forces and displacement, emphasizing that normal forces maintain the same direction while displacement can vary. Overall, the discussion reinforces that normal forces do not perform work due to their perpendicular nature to displacement.
t2r
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Hello everyone,
someone could explain me please, why the work of the normals forces are 0 ?



He used with conservation energy equations.
How should I refer to the displacement point ?

Thx everyone !
 
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Because the work done by a force is ##W= Fd\cos\theta##. The normal force is perpendicular to the displacement by definition in which case ##\theta =90^o## and ##\cos(90^o)=0##.
 
Well, the work is, by definition ##dW=\vec{F}\cdot d\vec{r}##, and a normal force is, again by definition a force which fulfils ##\vec{F}\cdot d\vec{r}=0##. So the work is zero almost by definition again.
 
The direction of the Normal forces is changed, and also the Δx is not downwards because the angular velocity.

Am I right ?
 

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t2r said:
The direction of the Normal forces is changed, and also the Δx is not downwards because the angular velocity.

Am I right ?
Nop, the direction of the Normal forces is the same before and after, and also the ##\Delta x## is downwards in one case and horizontal in the other. From where you can see that ##\vec{F}\cdot d\vec{r}=0## as we said before.
 
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