Conservation of Linear Momentum of exploding object

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Homework Help Overview

The problem involves the conservation of linear momentum in the context of an object that explodes into three fragments. The initial object is at rest, and the discussion focuses on determining the speed and direction of the third fragment based on the momentum of the other two fragments.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss analyzing the horizontal and vertical components of momentum separately. There are questions about how to apply the conservation of momentum principle and incorporate it into equations.

Discussion Status

Some participants have offered insights into the need for the total momentum to equal zero, given that the initial momentum is zero. There is exploration of the relationship between the fragments' velocities and their respective momentum vectors, but no consensus has been reached on the final calculations.

Contextual Notes

Participants are working under the assumption that momentum is conserved and are considering the implications of the initial object being at rest. There may be constraints related to the specific values and directions of the fragments that are still being clarified.

msesulka
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A 3.0-kilogram object initially at rest explodes and splits into three fragments. One fragment has a mass of 0.50 kg and flies off along the negative x-axis at a speed of 2.8 m/s, and another has a mass of 1.3 kg and flies off along the negative y-axis at a speed of 1.5 m/s. What are the speed and direction of the third fragment?
 
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I've been trying to figure this problem out for the past hour can anyone please help me?!
 
Consider the horizontal and vertical components of the linear momentum separately (since these components are perpendicular, they can be analyzed independently).
 
That's what i thought but i don't know how to incorporate that into the equation mv = mv0
 
The initial linear momentum is 0. Thus the final linear momentum is also 0, because momentum is conserved.
 
The total momentum of the three vectors need to be zero. This means that the third vector must be the negative of the resultant of the first two. Which means that the third vector has the negative x and y-components of the first two.
 

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