Conservation of Momentum - BOMB EXPLOSION question

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SUMMARY

The discussion centers on a physics problem regarding the conservation of momentum in a bomb explosion in space. The correct answer to the question posed is that the vector sum of the linear momenta of the fragments must be zero (option d). Kinetic energy is not conserved in this scenario, as the bomb was stationary before the explosion, resulting in zero initial kinetic energy. The participants clarify that while the momentum remains zero before and after the explosion, the fragments move independently, complicating the calculation of kinetic energy.

PREREQUISITES
  • Understanding of conservation laws in physics, specifically momentum and kinetic energy.
  • Familiarity with the concept of explosions and fragment motion in a vacuum.
  • Knowledge of basic equations of motion, particularly mv (before) = mv (after).
  • Ability to differentiate between rigid body motion and ensemble motion in physics.
NEXT STEPS
  • Study the principles of conservation of momentum in isolated systems.
  • Learn about kinetic energy calculations for systems with multiple moving parts.
  • Explore the implications of explosions in a vacuum versus in a gravitational field.
  • Investigate the differences between rigid body dynamics and ensemble dynamics in physics.
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of momentum and energy conservation in explosive events.

gcombina
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Homework Statement



QUESTION 1 :A stationary bomb explodes in space breaking into a number of small fragments. At the location of the explosion, the net force do to gravity is 0 Newtons. Which one of the following statements concerning the event is true?
a) Kinetic energy is conserved in the process
b) The fragments must have equal kinetic energies
c) The sum of the KE's of the fragments must be 0
d) The vector sum of the linear momenta of the fragments must be zero
e) The velocity of anyone fragment must be equal to the velocity of any other fragment

Homework Equations


mv (before) = mv (after)

The Attempt at a Solution


a) mv (before) = mv (after), velocity before is 0 and velocity after is 0 therefore, the KE is NOT conserved
b) there is NO KE as the bomb was stationary so it was zero velocity
c) KE must always be positive so it can NOT be 0
d) YES
e) The velocities of these fragments are zero, therefore the velocity of one fragment can be equal to other fragment so I don't understand this question
 
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gcombina said:
a) mv (before) = mv (after), velocity before is 0 and velocity after is 0
The velocity of what is zero after? There are many independently moving fragments.
If you mean the average velocity (weighted according to mass), you can't use that for finding the KE of an ensemble.
 
haruspex said:
The velocity of what is zero after? There are many independently moving fragments.
If you mean the average velocity (weighted according to mass), you can't use that for finding the KE of an ensemble.

I thought that because it said "stationary bomb" then the velocity was zero before it exploted
 
gcombina said:
I thought that because it said "stationary bomb" then the velocity was zero before it exploted
Sure, but you wrote that it is also zero afterwards.
 
haruspex said:
Sure, but you wrote that it is also zero afterwards.

right cause the conservation of momentum, am I right? velocity is zero before and its zero after
 
gcombina said:
right cause the conservation of momentum, am I right? velocity is zero before and its zero after
The momentum is zero before and after, but in the after condition the mass is made of many small parts. You can only use ##\frac 12 mv^2## for KE when the m is a rigid body (and you would have to add in rotational energy too. If it is an ensemble then you must sum the energies over the rigid components.
 
haruspex said:
The momentum is zero before and after, but in the after condition the mass is made of many small parts. You can only use ##\frac 12 mv^2## for KE when the m is a rigid body (and you would have to add in rotational energy too. If it is an ensemble then you must sum the energies over the rigid components.
wow, i don't understand you. Which option are you trying to explain to me? option a) or option e)?
 
gcombina said:
wow, i don't understand you. Which option are you trying to explain to me? option a) or option e)?
It relates to your reasoning on all except d), but does not necessarily change your answer. For instance, in a) you got the right answer, that KE is not conserved, despite apparently reasoning that it would be.
 
gcombina said:
I assume that the bomb explodes and the parts fly and then remain on the ground
What ground? The question only concerns the instants before and after the explosion.
 

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