- #1
CivilSigma
- 227
- 58
Homework Statement
Hello, I am having trouble understanding the logic behind the solution to the posted problem. How did they deduce the equation for "Just after impact" ? I don't see how
$$v_y = \sqrt{2g(0.6)}$$
What assumptions did they make or how did they get this simplified equation?
I understand how they got the formula for "Just before impact"
In the y direction:
$$mg(1.6)+0.5m(0)^2 = mg(0)+0.5mv_f^2$$
$$v = \sqrt{2g(1.6)}$$
But I don't see how they applied this formula for "just after impact"
Any guidance is really appreciated.
Thank you for your time.