Conservative fields in a transverse plane of a transmission line

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SUMMARY

A transmission line operates as a wave-guide for Transverse Electromagnetic (TEM) modes, where the absence of z-components for both electric (Ez) and magnetic (Hz) fields indicates that the fields in any transverse plane (xy plane) are conservative. This conclusion arises from the static nature of the electric field distribution, which remains unchanged over time. By applying Faraday's Law in its integral form and considering the static case, one can deduce that the line integral of the electric field around a closed path is zero, confirming the path-independence characteristic of conservative fields.

PREREQUISITES
  • Understanding of Transverse Electromagnetic (TEM) modes
  • Familiarity with Faraday's Law in integral form
  • Knowledge of conservative vector fields
  • Basic concepts of electric and magnetic field distributions
NEXT STEPS
  • Study the properties of Transverse Electromagnetic (TEM) modes in detail
  • Review the implications of Faraday's Law in both static and dynamic scenarios
  • Explore the mathematical definition and characteristics of conservative vector fields
  • Investigate the relationship between electric field distributions and static conditions
USEFUL FOR

Electrical engineers, physicists, and students studying electromagnetic theory, particularly those focusing on transmission lines and field theory.

maria clara
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Hello,

As far as I understand, a transmission line is simply a wave-guide for TEM modes.
If the waves are propagating in the z direction so Hz=Ez=0. How does this fact leads to the conclusion that in any transverse plane (xy plane) the fields are conservative?
Thanks a lot.
 
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maria clara said:
As far as I understand, a transmission line is simply a wave-guide for TEM modes. If the waves are propagating in the z direction so Hz=Ez=0. How does this fact leads to the conclusion that in any transverse plane (xy plane) the fields are conservative?

Since there's no z-component of H (or E), the electric field (magnetic field) distribution in any given transverse plane at any given instant of time is the same as the static electric-field distribution. Question: Why is this true?

With this information at hand, go back to Faraday's Law in integral form and look at the static case (i.e. d/dt=0). Question: What does it mean that the line integral is equal to zero?

EDIT: If you stop at path-independence, I obviously made it too easy for you. To really understand your problem you should look at the http://en.wikipedia.org/wiki/Conservative_vector_field#Definition" and understand how it applies to your scenario.
 
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