Consevative and non-conservative forces

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Homework Help Overview

The discussion revolves around a physics problem involving a toy cannon that uses a spring to launch a rubber ball, examining the forces at play, specifically conservative and non-conservative forces, and determining the point of maximum speed of the ball.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the relationship between the spring force and friction, questioning where the maximum speed occurs in relation to these forces. There is an attempt to set equations for force and acceleration, leading to confusion about the correct distance for maximum speed.

Discussion Status

Some participants have provided insights into the mechanics of the problem, suggesting that the maximum speed occurs when the spring force equals the frictional force. However, there is still uncertainty regarding the calculations and interpretations of distances involved.

Contextual Notes

Participants are navigating the complexities of the problem setup, including the initial compression of the spring and the effects of friction, while also addressing the need for clarity on the relationship between these forces.

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A toy cannon uses a spring to project a 5.39 g soft rubber ball. The spring is originally compressed by 4.99 cm and has a force constant of 8.04 N/m. When the cannon is fired, the ball moves 15.8 cm through the horizontal barrel of the cannon, and there is a constant frictional force of 0.0328 N between the barrel and the ball.



At what point does the ball have maximum speed?


I do not know where to start... If I set F=fx and F=ma, then I get speed at 4.99cm which is incorrect. Can someone please help?
 
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Imagine the process. At first, the spring is stronger than friction and accelerates the ball. At some point, friction overcomes the spring force and the ball starts slowing down. So the point of maximum speed is the point where these two forces are equal.
 
Thank you so much for responding.
If that is the case, my answer still does not make sense. If Kx=friction, then 8.04x=0.0328 which causes x to be 0.4079cm.
 
That's the distance from equilibrium. Remember that the spring is originally 4.99 cm from equilibrium.
 
thank you, thank you, thank you! :-)
 

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