Consevative and non-conservative forces

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SUMMARY

The discussion focuses on the mechanics of a toy cannon that uses a spring to launch a 5.39 g rubber ball. The spring has a force constant of 8.04 N/m and is initially compressed by 4.99 cm. The ball travels 15.8 cm in the barrel, facing a constant frictional force of 0.0328 N. The maximum speed of the ball occurs when the spring force equals the frictional force, which is determined to be at a distance of 0.4079 cm from the equilibrium position of the spring.

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  • Understanding of Hooke's Law and spring constants
  • Knowledge of Newton's second law of motion (F=ma)
  • Familiarity with concepts of frictional forces
  • Basic principles of energy conservation in mechanical systems
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  • Calculate the potential energy stored in the spring using the formula PE = 0.5 * k * x^2
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A toy cannon uses a spring to project a 5.39 g soft rubber ball. The spring is originally compressed by 4.99 cm and has a force constant of 8.04 N/m. When the cannon is fired, the ball moves 15.8 cm through the horizontal barrel of the cannon, and there is a constant frictional force of 0.0328 N between the barrel and the ball.



At what point does the ball have maximum speed?


I do not know where to start... If I set F=fx and F=ma, then I get speed at 4.99cm which is incorrect. Can someone please help?
 
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Imagine the process. At first, the spring is stronger than friction and accelerates the ball. At some point, friction overcomes the spring force and the ball starts slowing down. So the point of maximum speed is the point where these two forces are equal.
 
Thank you so much for responding.
If that is the case, my answer still does not make sense. If Kx=friction, then 8.04x=0.0328 which causes x to be 0.4079cm.
 
That's the distance from equilibrium. Remember that the spring is originally 4.99 cm from equilibrium.
 
thank you, thank you, thank you! :-)
 

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