Constant Acceleration of a motorist

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SUMMARY

A speeding motorist traveling at 120 km/h (33.33 m/s) is pursued by a police officer accelerating at 10.0 km/h/s (2.778 m/s²). To determine the time it takes for the officer to catch the motorist, the distances covered by both must be equal. Using the equations of motion, specifically Vf = Vi + at and D = Vit + 1/2at², the problem can be solved by equating the distances of both the motorist and the officer. The final speed of the officer at the moment of catching the motorist can also be calculated using the same equations.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Ability to convert units (e.g., km/h to m/s)
  • Familiarity with concepts of constant acceleration
  • Basic algebra for solving equations
NEXT STEPS
  • Practice solving problems involving constant acceleration using kinematic equations
  • Learn about graphical representations of motion (position vs. time graphs)
  • Explore real-world applications of acceleration in law enforcement scenarios
  • Study the effects of varying acceleration on pursuit scenarios
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in the practical applications of motion equations in real-world scenarios.

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Homework Statement



A speeding motorist traveling 120 km/h passes a stationary police officer. The officer <i>immediately</i> begins pursuit at a constant acceleration of 10.0 km/h/s. How much time will it take for the police officer to reach the speeder, assuming that the speeder maintains a constant speed? How fast will the police officer be traveling at this time?


Homework Equations


These are the equations we have to pull from in class:

Vf=Vi + at
D= Vit + 1/2at2
D=1/2t (Vf+Vi)
Vf2=Vi2 + 2aD



The Attempt at a Solution


I fixed the mixed units so that 120 km/h equals 33.33 m/s and 10 km/h/s equals 2.778 m/s2
The officer's Vi is 0.
Distance(D) of the motorist and Distance(D) of the officer should be the same, as well as their times(t).
So, Dm=Do
and tm=to
I've tried solving the above equations for a distance or a time that i can then sub back in, but nothing seems to be working. I just need a little push in the right direction.
 
Physics news on Phys.org
Write equations for motorist and officer starting at t=0 and apparently x=0 for each.

When the X's equal then the motorist gets his ticket.
 

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