Constant Acceleration Ratio to Constant Velocity

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SUMMARY

The discussion centers on a physics problem involving a car traveling at a constant speed and a motorcycle accelerating to match that speed. The solution reveals that the ratio of the distance traveled by the motorcycle to the distance at which it matches the car's speed is d/4. The key equation for motion, X = Xi + Vi(t) + 1/2 a t^2, is referenced, although specific values for initial conditions are not provided. The conclusion emphasizes that this ratio holds universally regardless of the specific values of velocity and acceleration.

PREREQUISITES
  • Understanding of kinematic equations, specifically X = Xi + Vi(t) + 1/2 a t^2
  • Knowledge of constant acceleration and constant velocity concepts
  • Ability to manipulate algebraic expressions to derive relationships
  • Familiarity with basic physics principles related to motion
NEXT STEPS
  • Explore kinematic equations in detail, focusing on their applications in various motion scenarios
  • Learn how to derive distance and time relationships in constant acceleration problems
  • Practice solving physics problems involving multiple objects with different velocities and accelerations
  • Investigate the implications of universal ratios in physics problems
USEFUL FOR

Students studying physics, particularly those focusing on kinematics, educators teaching motion concepts, and anyone interested in problem-solving strategies for acceleration and velocity scenarios.

Bill48
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Homework Statement


A car traveling at an unspecified constant speed passes a parked motorcycle cop. The motorcycle accelerated at an unspecified constant acceleration and reaches the car at unspecified distance d. At what point did the motorcycle's speed match that of the car, expressed as a ratio of d divided by a denominator.

Homework Equations


None that I know of.

The Attempt at a Solution


This question was on a test. Per the professor no one in the class got it. The answer is d/4. I've been trying to figure out how that was obtained but have no idea. It is obviously a universal ratio since the value of velocity and acceleration are not given.
 
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The car and the motorcycle both use the same equation. Do you know the equation?
 
X = Xi + Vi(t) + 1/2 a t^2 is the closest equation I can think of. Xi is initial location, Vi is initial velocity. a is acceleration. But since I have no values I don't know how to proceed.
 
You do have initial values.
  1. What is X0 for each person?
  2. What is v0 for each person?
  3. What is a for each person?
 
X0 is the same for both. V0 for the car is not given, but is zero for the motorcycle. A for the car is zero since it is traveling at a constant velocity. A for the motorcycle is constant but not given.
 
Correct. Now what is the relationship of their distance traveled and how can you write that in a single equation?
 
The relationship of their distance traveled is d/4. The prof gave us the answer when he returned our papers. I have no idea how that answer was obtained.
 
What is the final distance equation for the car with the zero elements removed?
 
I have no idea, that's why I posted the question. If you're not going to explain then quit wasting my time.
 
  • #10
I am not wasting your time. I am trying to help you understand how to solve it. The rules for homework questions are that people cannot just give answers.
You gave me the equation of motion for the car and motorcycle so it should be a simple thing to write them without the zero terms.
 
  • #11
I know the answer. The answer is d/4.
 
  • #12
Bill48 said:
I know the answer. The answer is d/4.
Getting the solution directly won't get you anywhere.

Once you get the equations without zero terms. What does the df represent in each equation? Can you use it in away to perhaps combine the equations together?

You will get to a really interesting fact. Use the kinematic equations again to get the value of time need to for the motorcycle's velocity to equal the cars velocity.

The rest is obvious.
 
  • #13
Bill48 said:

Homework Statement


A car traveling at an unspecified constant speed passes a parked motorcycle cop. The motorcycle accelerated at an unspecified constant acceleration and reaches the car at unspecified distance d. At what point did the motorcycle's speed match that of the car, expressed as a ratio of d divided by a denominator.

Homework Equations


None that I know of.

The Attempt at a Solution


This question was on a test. Per the professor no one in the class got it. The answer is d/4. I've been trying to figure out how that was obtained but have no idea. It is obviously a universal ratio since the value of velocity and acceleration are not given.

You could have thought like this:

If this problem can be solved it must be the same solution for all velocities and accelerations. So, perhaps just choose any numbers and try to solve the problem. Then, perhaps, choose a different set of numbers and try to solve the problem again.

E.g. speed = ##20 m/s##, acceleration = ##5m/s^2##. You can now calculate the two distances and compare them.

Then, try again with a different velocity and acceleration.

You should find that in both cases the total distance is 4 times the first distance.

Solving with specific numbers might give you some ideas on how to solve the general problem, which is going to be all algebra and no arithmetic.
 
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