Calculating Time for Constant Acceleration: Motorcycle Velocity Change

[Erenjaeger]

Homework Statement

A motorcycle has a constant acceleration of 2.80 m/s2. Both the velocity and acceleration of the motorcycle point in the same direction. How much time is required for the motorcycle to change its speed from (a)40.9 to 50.9 m/s, and (b)70.9 to 80.9 m/s?
[/B]

Homework Equations

V_f = V_i + a*t[/B]

The Attempt at a Solution

using that kinematic formula,
for a) 50.9=40.9+2.8*t
then divide both sides by 40.9+2.8 to solve for t
answer = 4.04[/B]
and same thing with b) but in both cases the answer is coming up as wrong. what have i done wrong?

 

[collinsmark]

Homework Statement

A motorcycle has a constant acceleration of 2.80 m/s2. Both the velocity and acceleration of the motorcycle point in the same direction. How much time is required for the motorcycle to change its speed from (a)40.9 to 50.9 m/s, and (b)70.9 to 80.9 m/s?
[/B]

Homework Equations

V_f = V_i + a*t[/B]

The Attempt at a Solution

using that kinematic formula,
for a) 50.9=40.9+2.8*t
then divide both sides by 40.9+2.8 to solve for t
answer = 4.04[/B]
and same thing with b) but in both cases the answer is coming up as wrong. what have i done wrong?

You should check your algebra.

50.9 = 40.9 + 2.8t

is not the same thing as

50.9 = (40.9 + 2.8)t.

And for that matter, neither one gives an answer of 4.04 sec. So I'm not really sure what happened there.

(Hint, you can't just add 40.9 plus 2.8 that way. That's not the way algebra works.)

 

[Erenjaeger]

You should check your algebra.

50.9 = 40.9 + 2.8t

is not the same thing as

50.9 = (40.9 + 2.8)t.

And for that matter, neither one gives an answer of 4.04 sec. So I'm not really sure what happened there.

(Hint, you can't just add 40.9 plus 2.8 that way. That's not the way algebra works.)

oh right, so basically i have to get 2.8t on its own and then divide by 2.8??

 

[collinsmark]

oh right, so basically i have to get 2.8t on its own and then divide by 2.8??

Yes, that is the correct way.

 

[Erenjaeger]

Yes, that is the correct way.

cool thanks!