Constant Functions: ε-δ Proof for Continuity

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SUMMARY

A constant function defined on a closed interval is continuous on that interval, as demonstrated through an ε-δ proof. Given a constant function f(x) = c, the difference f(x) - f(a) equals zero for any point a within the interval. Since the absolute difference is always zero, it satisfies the ε-δ definition of continuity, confirming that for any ε > 0, there exists a δ such that |f(x) - f(a)| < ε for all x within δ of a.

PREREQUISITES
  • Understanding of ε-δ definitions of continuity
  • Familiarity with closed intervals in real analysis
  • Basic knowledge of functions and limits
  • Ability to manipulate inequalities
NEXT STEPS
  • Study the ε-δ definition of continuity in depth
  • Explore proofs of continuity for other types of functions, such as polynomial and rational functions
  • Learn about the implications of continuity on differentiability
  • Investigate the properties of closed intervals in real analysis
USEFUL FOR

Students of calculus, mathematics educators, and anyone interested in understanding the foundational concepts of continuity in real analysis.

Niles
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Homework Statement


Hi all

How can I show that a constant function defined on a closed interval is continuous on that same interval using a ε-δ proof?

I have f(x)=c on the interval. Then I write

f(x)-f(a) = c-c = 0

for some point a in the interval. But what to do from here?
 
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This is a very easy proof. Isn't 0 < epsilon for any positive epsilon?
 

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