Graduate Constructing a sequence in a manifold

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The discussion focuses on proving that a submanifold S of a manifold M is an embedded submanifold under the condition that every smooth function on S can be extended to a neighborhood W of S in M. The initial argument assumes S is not embedded, leading to a contradiction through the construction of a sequence converging to a point p not contained in any slice chart. The key point is that the first countability of manifolds allows for the construction of such a sequence, supporting the claim. The conclusion is that the properties of smooth functions and the structure of manifolds ensure S must be an embedded submanifold. This reasoning solidifies the relationship between the smooth functions and the topology of the manifold.
JYM
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Given S is a submanifold of M such that every smooth function on S can be extended to a smooth function to a neighborhood W of S in M. I want to show that S is embedded submanifold.
My attempt: Suppose S is not embedded. Then there is a point p that is not contained in any slice chart. Since a submanifold is locally embedded, let U be a neighborhood of p that is embedded. Consider a smooth function on S that is supported in U and equal to 1 at p. If there is a sequence x_n in S-U that converges to p, then since f can be extended to a smooth function F on W but then 0=F(x_n) converges to F(p)=1, which is contradiction. My difficulty is to justify such a sequence exists. Please provide me your help.
 
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No. We can construct such a sequence. Now I get the idea; the result follows from first countablity of manifolds ( as second countable is first countable).
 

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