Constructing Cones as Orbifolds: Fundamental Domain for an Identification

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Homework Help Overview

The discussion revolves around constructing cones as orbifolds using complex coordinates and specific identifications in the complex plane. The original poster presents a problem involving the identification of points in the complex plane defined by a complex exponential function, seeking to determine a fundamental domain for this identification.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to define a fundamental domain based on the argument of the complex number and questions the correctness of their answer. Other participants raise concerns about the lack of justification for the proposed fundamental domain and suggest that the identification may not cover the entire complex plane.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the fundamental domain and questioning the assumptions made in the original post. Some participants provide examples to illustrate their points, indicating a productive exchange of ideas without reaching a consensus.

Contextual Notes

Participants note the importance of the relationship between the integers M and N, particularly their relative primality, and how this affects the identification and the resulting fundamental domain. There is an emphasis on the implications of Bezout's identity in the context of the problem.

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Homework Statement

Consider the ##(x,y)## plane and the complex coordinate ##z=x+iy##. The identification ##z \sim z\ exp^{(\frac{2 \pi i}{N})}##, with ##N## an integer greater than 2, can be used to construct a cone.

Examine now the identification ##z\sim z\ e^{2 \pi i \frac{M}{N}}, N>M \geq 2,## where ##M## and ##N## are relatively prime integers (that is, the greatest common divisor of M and N is 1). Determine a fundamental domain for the identification.

Homework Equations



The Attempt at a Solution



A fundamental domain for the identification is ##0 \leq arg(z) < 2 \pi \frac{Ma+Nb}{N},## because ##Ma+Nb=1## for two integers ##a## and ##b##.

Would you say that my answer is correct?
 
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bumpp!
 
You haven't given any reasons for your answer so I doubt that many teachers would accept it.
 
Here's my explanation:

One may guess that the fundamental domain is provided by the points ##z## that satisfy ##0 \leq arg(z) < 2 \pi \frac{M}{N}##. However this is not true. Take, for example. ##M = 2## and ##N = 3##. In this case, the identification becomes

##z \sim \exp^{(2 \pi i \frac{2}{3})}z ##

and the fundamental domain becomes

##0 \leq arg(z) < 2 \pi \frac{2}{3}##.

Therefore, the fundamental domain covers ##\frac{2}{3}## of the complex plane.
Therefore, not all the points of the fundamental domain can be identified with points on the remaining ##\frac{1}{3}## of the complex plane.

However, this is a possible fundamental domain for the identification:

##0 \leq arg(z) < 2 \pi \frac{Ma+Nb}{N}##

By Bezout's identity, if ##M## and ##N## are non-zero integers, and if ##d## is their greatest common divisor, then there exist integers ##a## and ##b## such that ##aM+bN=d##.

In our case, ##M## and ##N## are relatively prime integers, so that their greatest common divisor is 1. Therefore, there exist integers ##a## and ##b## such that ##aM+bN=1##.

This is very helpful because, now, the entire complex plane can be broken down into the fundamental domain and other regions whose points can be identified with points in the fundamental domain.

What do you think? :frown:
 
bumpp!
 

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