(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

380g of a liquid at 12'C in a copper calorimeter weighing 90g is heating at a rate of 20 watt for exactly 3 minutes to produce a temperature of 17'C. If the specific heat capacity of copper is 40Jkg-1K-1, the thermal capacity of the heater is negligible, and there is a negligible heat loss to the surroudnings, obtain a value for the specific heat capacity of the liquid.

2. Relevant equations

VxI = MC(x2 - x1) + q

3. The attempt at a solution

I genuienly don't have a clue about this.

+q is negligible.

So what are we meant to do for this? I assume we get two values for the equation of the calorimeter and the liquid, minus them and make it C =.

Is that correct? But what values do we sub in for where (I know what everything stands for =/).

Any help is apprectiated!

Thank you.

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# Homework Help: Continuous Flow Calorimeter (SHC)

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