How to Calculate the Specific Heat Capacity of the Calorimeter?

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Homework Help Overview

The problem involves calculating the specific heat capacity of a calorimeter containing oil and brass. The scenario includes specific masses and temperatures of the substances involved, with a focus on energy transfer and heat calculations.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the heat calculations for the oil and brass, questioning how to incorporate the calorimeter's heat gain into the overall energy balance. There is also clarification sought regarding the temperature change for the calorimeter.

Discussion Status

The discussion is ongoing, with participants providing calculations and seeking confirmation on specific aspects of the problem. Some guidance has been offered regarding the relationship between the temperature changes of the oil and calorimeter.

Contextual Notes

Participants are working within the constraints of given specific heat capacities and masses, while also addressing potential assumptions about temperature changes across different materials in the calorimeter.

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Homework Statement



A calorimeter contains of 70g oils at temperature of 30oC.If a piece of brass with a mass of 125g heat up until 100oC.After that a brass put in that calorimeter and final temperature of the mixed is 44oC.Calculate the specific heat capacity (c) of the calorimeter if its mass is 100g.(Given c of oil =1.52Jg-1oC-1 & c of brass =0.42Jg-1oC-1)

Homework Equations



Q=mcθ

The Attempt at a Solution



Qoil=70(1.52)(14)=1489.6J
Qbrass=125(0.42)(56)=2940J

Then I stuck.How to find temperature & Q of calorimeter?
 
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Qoil=70(1.52)(14)=1489.6J
Qbrass=125(0.42)(56)=2940J

Find heat gained by the calorimeter. And then

Qbrass = Qoil + Qcal.
 
Thanks for the help,but just to make sure,is temperature change for calorimeter=44-30=14?
 
kai92 said:
Thanks for the help,but just to make sure,is temperature change for calorimeter=44-30=14?

Yes. Oil is in the calorimeter. So the change in temperature of oil and the calorimeter is the same.
 

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