How to Calculate the Specific Heat Capacity of the Calorimeter?

[kai92]

Homework Statement

A calorimeter contains of 70g oils at temperature of 30^oC.If a piece of brass with a mass of 125g heat up until 100^oC.After that a brass put in that calorimeter and final temperature of the mixed is 44^oC.Calculate the specific heat capacity (c) of the calorimeter if its mass is 100g.(Given c of oil =1.52Jg^-1oC^-1 & c of brass =0.42Jg^-1oC^-1)

Homework Equations

Q=mcθ

The Attempt at a Solution

Q_oil=70(1.52)(14)=1489.6J
Q_brass=125(0.42)(56)=2940J

Then I stuck.How to find temperature & Q of calorimeter?

 

[rl.bhat]

Qoil=70(1.52)(14)=1489.6J
Qbrass=125(0.42)(56)=2940J

Find heat gained by the calorimeter. And then

Qbrass = Qoil + Qcal.

 

[kai92]

Thanks for the help,but just to make sure,is temperature change for calorimeter=44-30=14?

 

[rl.bhat]

Thanks for the help,but just to make sure,is temperature change for calorimeter=44-30=14?

Yes. Oil is in the calorimeter. So the change in temperature of oil and the calorimeter is the same.