Continuous function f(t), t >= 0

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SUMMARY

The discussion centers on solving the integral equation involving the continuous function f(t) defined by the equation 1 + ∫(from a to x²) e^t f(t) dt = ln(1 + x²). The solution involves differentiating both sides with respect to x, applying the Leibniz rule for differentiation under the integral sign. The derived function is f(t) = e^(-t) / (1 + t). This function allows for the determination of the positive constant a by substituting f(t) back into the integral.

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aselin0331
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Homework Statement



1+ integrand of e^t f(t) dt (from a to x^2) = ln (1+x^2)



Homework Equations





The Attempt at a Solution




I managed to sub in x^2 and derive the left then moved the one to the other side and differentiated the right hand side as well (a hint attached to the question: to find f(t) differentiate both sides in respect to x)

It's asking us to find a positive constant a. How do I do that?

Thanks :)
 
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Differentiate under the integral sign, there is a rule for this if
<br /> F(x)=\int_{a(x)}^{b(x)}f(x,t)dt<br />
then:
<br /> F&#039;(x)=f(x,b(x))b&#039;(x)-f(x,a(x))a&#039;(x)+\int_{a(x)}^{b(x)}\frac{\partial f}{\partial x}dt<br />
Use this expression to find f(t), I obtain f(t) as:
<br /> f(t)=\frac{e^{-t}}{1+t}<br />
Insert this into the integral and the value of a will pop out.
 

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