Continuous function from Continuous functions to R

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SUMMARY

The discussion centers on the continuity of the function F(f) = f(0) within the space of continuous functions C[0,1], using the distance metric d(f,g) = √(∫₀¹ (f(x) - g(x))² dx). The conclusion reached is that F is not continuous, as demonstrated by the sequence of functions f_n(x) = (1 - x²)ⁿ, which converges to f(x) = 0 in the metric space, yet F(f_n) does not converge to F(f). This analysis applies the epsilon-delta definition of continuity in the context of metric spaces.

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  • Understanding of metric spaces and their properties
  • Familiarity with the epsilon-delta definition of continuity
  • Knowledge of real analysis concepts
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  • Study the properties of metric spaces in detail
  • Explore the epsilon-delta definition of continuity further
  • Learn about convergence of sequences in functional analysis
  • Investigate examples of continuous and discontinuous functions in C[0,1]
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Students of real analysis, mathematicians focusing on functional analysis, and educators teaching concepts of continuity in metric spaces.

PingPong
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Hi,

I think I've gotten this problem, but I was wondering if somebody could check my work. I still question myself. Maybe I shouldn't, but it feels better to get a nod from others.

Homework Statement


Consider the space of functions C[0,1] with distance defined as:

[tex]d(f,g)=\sqrt{\int_0^1 (f(x)-g(x))^2 dx}[/tex].

Suppose we have a function F(f)=f(0). Is this function continuous?


Homework Equations


Epsilon-delta definition of continuity.


The Attempt at a Solution


My answer is no, and my reasoning is based on a bit of real analysis that I remember that I'm trying to apply to metric spaces. In real analysis, a function f is continuous if every sequence [itex]x_n\rightarrow x[/itex] implies that [itex]f(x_n)\rightarrow f(x)[/itex]. So interpreting this for a metric space, a function from one metric space to another is continuous if every sequence such that [itex]f_n\rightarrow f[/itex] implies that [itex]F(f_n)\rightarrow F(f)[/itex].

So, I consider the sequence of functions [itex]f_n(x)=(1-x^2)^n[/itex] whose elements are certainly in C[0,1], and the function [itex]f(x)=0[/itex] which is also in C[0,1]. Now, [itex]d(f,f_n)\rightarrow 0[/itex], so the sequence converges to f. But on the other hand, [itex]F(f_n)=f_n(0)=1\ne F(f)=0[/itex]. Thus the function F is not continuous.

Does this proof work? Thanks in advance!
 
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Yes, I think that works.
 
Thank you very much!
 

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