Contour integration by parametisation

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The discussion focuses on evaluating the contour integral ∫C dz f(z) for f(z) = z^n, where n is a positive integer. The contour C consists of two segments: from z = 0 to z = 2 and from z = 2 to z = 2 + i. The user attempted to split the contour into two sub-contours, ϒ1 and ϒ2, and applied the integral formula ∫ϒ f(z) dz = ∫ab dt f(ϒ(t))ϒ'(t) to compute the integral. The resulting expression, (2+i)(n+1)/(n+1), raised concerns about its validity, particularly regarding the expectation of a real result.

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Poirot
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Homework Statement


Determine, by explicit parameterisation,

C dz f(z), where f(z) = z^n , n ∈ Z, n > 0
and C is the line segment from z = 0 to z = 2 together with the line segment from z = 2 to z = 2 + i.

Homework Equations


ϒ f(z) dz = ∫ab dt f(ϒ(t))ϒ'(t) where ϒ'(t)≈dz/dt

The Attempt at a Solution


Splitting C into two sub contours ϒ1 = {z=x, x ∈ [0 , 2]} and ϒ2 = {z=y, y ∈ [2 , 2+i]}. Then using the equation above to integrate over both and sum. This gave and answer which I really can't gauge whether is correct or not.

(2+i)(n+1)/(n+1)

But my lecturer gave us a rough check guide and said that if what you start with is a real number then your answer should be real also. Thus am skeptical of my answer.

Any help on the method, answer or general help with this would be greatly appreciated.

Thanks!
 
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Poirot said:

Homework Statement


Determine, by explicit parameterisation,

C dz f(z), where f(z) = z^n , n ∈ Z, n > 0
and C is the line segment from z = 0 to z = 2 together with the line segment from z = 2 to z = 2 + i.

Homework Equations


ϒ f(z) dz = ∫ab dt f(ϒ(t))ϒ'(t) where ϒ'(t)≈dz/dt

The Attempt at a Solution


Splitting C into two sub contours ϒ1 = {z=x, x ∈ [0 , 2]} and ϒ2 = {z=y, y ∈ [2 , 2+i]}. Then using the equation above to integrate over both and sum. This gave and answer which I really can't gauge whether is correct or not.

(2+i)(n+1)/(n+1)

But my lecturer gave us a rough check guide and said that if what you start with is a real number then your answer should be real also. Thus am skeptical of my answer.

Any help on the method, answer or general help with this would be greatly appreciated.

Thanks!
It's not clear what your lecturer was talking about, or if you have fully understood what he said, but I have never heard of such a "rough check" on open contour integrals.

In fact, a similar problem is contained in this article (pp. 4-5) where f(z) = z2 and the contour is dog-legged like the one for your problem:

https://math.dartmouth.edu/archive/m43s12/public_html/notes/class6.pdf

The calculation starts out with a real result on C1 and gives a complex result on C2 with a net result which is complex. :wink:
 

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