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Homework Help: Control problem. Transfer function of an electrical system

  1. Aug 14, 2010 #1
    [URL]http://img28.mediafire.com/bacfa47633147eefb0c3433511d3f1415g.jpg[/URL]

    1. Electrical system given. Find a transfer function. Correct answer UR(s)/U(s)=1/(s+2)

    2. My attempt
    Use Kirchhoff's voltage law u(t)-i(t)*R1-UR(t)=0; u(t)=i(t)R1+uR(t); apply Laplace Transform (L.T.) U(s)=I(s)R1+UR(s)

    i(t)=i1(t)+i2(t)=1/L*[tex]\int[/tex]uR(t) dt+uR(t)/R2; take a L.T. assuming zero initial conditions I(s)=1/(L*s)*UR(s)+UR(s)/R2=UR(s)[1/(L*s)+1/R2]; since L=R1=R2=1 I(s)=UR(s)*(1/s+1); UR(s)=I(s)/(1/s+1)

    H(s)=HR(s)/U(s)=[I(s)/(1/s+1)]/[I(s)R1+UR(s)]=[I(s)/(1/s+1)]/[I(s)+I(s)/(1/s+1)]=[1/(1/s+1)]/[1+1/(1/s+1)]=s/(1+2s)

    Where am I making a mistake?
     
    Last edited by a moderator: Apr 25, 2017
  2. jcsd
  3. Aug 14, 2010 #2
    I'm not going to look through your nonlatex work but I'll post a set up that should be correct.

    [tex]\frac{u_R(t)-u(t)}{R_1}+\frac{u_R(t)}{sL}+\frac{u_R(t)}{R_2}=0[/tex]
     
  4. Aug 28, 2010 #3
    I am assuming you are using the Kirchhoff's current law?

    I agree with everything, except the frac [tex]\frac{u_R(t)}{sL}[/tex].Can you, please explain, how does this results in current? How can you have a time domain function in the numerator and a frequency variable in the denominator?
     
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