Control Volume: Linear Momentum

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SUMMARY

The discussion centers on the application of the linear momentum equation for control volumes in fluid dynamics, specifically addressing the calculation of flow velocity (V2) from section 2. The correct expression for V2 is V*cos(60), derived from the constant velocity assumption and the geometry of the flow. The participant initially misinterpreted the scenario as having two outlets, but it was clarified that the depiction is a 2-D representation of a 3-D flow situation, confirming that there is only one outlet contributing to the momentum calculation.

PREREQUISITES
  • Understanding of linear momentum equations in fluid dynamics
  • Familiarity with control volume analysis
  • Basic knowledge of vector components and trigonometry
  • Experience with 2-D and 3-D flow representations
NEXT STEPS
  • Study the derivation of the linear momentum equation in control volumes
  • Learn about the implications of flow geometry on velocity calculations
  • Explore the application of trigonometric functions in fluid dynamics
  • Investigate 3-D flow scenarios and their representation in 2-D diagrams
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Students and professionals in fluid dynamics, mechanical engineers, and anyone involved in analyzing control volumes and momentum in fluid flow systems.

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Homework Statement



I know how to apply the linear momentum equation for the control volume, but I am not sure why the V2 (velocity of flow from section 2) is V*cos(60).

The only reason I can see is the velocity being constant. And since there are two outlet with equal area, the velocity is half? (1/2)V*cos(60) + (1/2)V*cos(60)= V*cos(60)

I just want to make sure my reasoning is right.

Thnx
 

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There are not two outlets.
This is a 2-D depiction of a 3-D situation.
 

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