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Show that Σ[tex]_{n=1}^\infty ln(1 -1/n^2) = -ln 2[/tex]

I'm not sure how to do this. Should I use telescopic sums or should I make a function [tex]y = ln(1 - 1/n^2)[/tex]? Is it possible to use telescopic sums here?

I'm not sure how to do this. Should I use telescopic sums or should I make a function [tex]y = ln(1 - 1/n^2)[/tex]? Is it possible to use telescopic sums here?

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