# Convergence of this sequence .

1. Jun 10, 2013

### bs vasanth

1. The problem statement, all variables and given/known data
find the limit n$\rightarrow$∞ of 10n/ n!

2. Relevant equations
L hospital rule

3. The attempt at a solution
took log and separated the num and denom as:
n ln10-ln(n!)
n ln10-n ln(n)+n
1/n ( ln10 - ln(n)+1)
now i applied l hospital rule
then i got lim n$\rightarrow$∞ as 0.So the actual answer is 1. (e0)
I just want to know if the approach is correct.

2. Jun 10, 2013

### Fightfish

I'm afraid I don't see how you transition between these two steps.
Also, intuitively the factorial function should dominate and the limit should be zero.

3. Jun 10, 2013

### bs vasanth

my bad ,in my desperate attempt to get a ratio, I did that stupid thing. How do we solve it beyond intuition?

4. Jun 10, 2013

### Fightfish

From n ln10-n ln(n)+n, you can combine all the terms into a single expression. Taking the limit, you will find that the expression tends to minus infinity. The limit of the original expression is then 0.

5. Jun 10, 2013

### bs vasanth

n*ln(10e/n) this is what i am getting , and it is not -infinity .

6. Jun 10, 2013

### Dick

Yes, the limit of that is -infinity. n goes to +infinity. What does ln(10e/n) do?

7. Jun 10, 2013

### bs vasanth

I took n out , then
n( ln10-lnn +1 )
n(ln10-lnn+lne)
n ln(10e/n)
i don't know what to do after this.

8. Jun 10, 2013

### bs vasanth

Are you saying that ln0 is taken as -inf, but there is also n before that right which becomes +inf.

9. Jun 10, 2013

### HallsofIvy

Staff Emeritus
The ratio test gives: $a_{n+1}/a_n= (10^{n+1}/(n+ 1)!)(n!/10^n)= (10^{n+1})/10^n)(n!/(n+1)!)= 10/(n+1)$ goes to 0 as n goes to 0. Strictly speaking, the ratio test shows that $$\sum a_n$$ converges but if that is so, then, of course, the sequence $\{a_n\}$ converges to 0.

(The converse is not necessarily true. For example, $\{1/n\}$ clearly converges to 0 but the sum $$\sum 1/n$$ does NOT converge so the ratio test does not work.)

Last edited by a moderator: Jun 11, 2013
10. Jun 10, 2013

### Office_Shredder

Staff Emeritus
n*ln(10e/n) if n is really big is a really big positive number multiplied by a really big negative number. What is that going to be?

11. Jun 12, 2013

### bs vasanth

Now i get it , it is going to really big negative number, so -inf.
therefor the answer for the original question is 0.
thankyou everyone.