# Convert a Laplace Function to image & real part

1. Nov 14, 2012

### baby_1

Hello
if our function is

how it convert to ?

2. Nov 14, 2012

### LCKurtz

That denominator is $\omega(-\omega T + j)$. Do you see why? Just multiply the numerator and denominator by $(-\omega T - j)$ and put it in $a+bj$ form. I assume those squiggles are squared symbols, as in $T^2$.