Convert LNA 433MHz Signal (21dB) to DC Voltage - Ryan's Question

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SUMMARY

The discussion centers on converting a 433MHz LNA signal (21dB) to a DC voltage. To lower the frequency to approximately 50MHz, a mixer circuit is recommended. For converting the amplitude of a 50MHz sine wave signal to a proportional DC voltage, a detector diode is the appropriate solution. These components are essential for achieving the desired signal processing in Ryan's scenario.

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RLovelett
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My scenario:
LNA 433MHz signal (21dB) from antenna and the difference between the two signals with a 4.1dB gain. I would like to take the result of the difference amplifier an produce a DC value that is proportional to the output.

Question 1:
What type of circuit would lower the frequency to something like 50MHz?

Question 2:
What type of circuit would take the amplitude of a 50MHz sine wave signal and convert it to a DC voltage that is proportional?

Many thanks!
Ryan
 
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Answer 1:
A mixer

Answer 2:
A detector diode.
 

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